Chapter 15: Problem 59
If one defines a variable mass \(m_{\text {var }}=\gamma m\), then the relativistic momentum \(\mathbf{p}=\gamma m \mathbf{v}\) becomes \(m_{\text {var }} \mathbf{v}\) which looks more like the classical definition. Show, however, that the relativistic kinetic energy is not equal to \(\frac{1}{2} m_{\mathrm{var}} v^{2}\)
Short Answer
Step by step solution
Define Variables and Formulas
Relativistic Kinetic Energy Formula
Compare Classical and Relativistic Kinetic Energies
Analyze Differences in Formulas
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Lorentz Factor
- When an object moves much slower than the speed of light, \( \gamma \approx 1 \) and relativistic effects are negligible.
- As the object's speed \( v \) increases towards \( c \), \( \gamma \) increases, leading to more noticeable relativistic effects.
Relativistic Mass
This term \( m_\text{var} \) emphasizes that the effective inertial mass of an object is velocity-dependent. As a result:
- The faster an object moves, the more massive it seems, due to \( \gamma \).
- At speeds approaching \( c \), \( \gamma \) increases and so does the relativistic mass.
Classical Mechanics
In classical mechanics, concepts like momentum and kinetic energy have simpler forms:
- Momentum \( \mathbf{p} = m \mathbf{v} \)
- Kinetic energy \( T_\text{classical} = \frac{1}{2} m v^2 \)
Speed of Light
Several key points concerning the speed of light include:
- Nothing with mass can travel at or faster than the speed of light, as this would require infinite energy.
- Light travels at \( c \) in a vacuum, and this speed is invariant—meaning all observers, regardless of their relative motion, measure the speed of light as \( c \).