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Find the Hamiltonian \(\mathscr{H}\) for a mass \(m\) confined to the \(x\) axis and subject to a force \(F_{x}=-k x^{3}\) where \(k>0 .\) Sketch and describe the phase-space orbits.

Short Answer

Expert verified
The Hamiltonian is \( \mathscr{H} = \frac{p^2}{2m} - \frac{k}{4}x^4 \). Phase-space orbits are closed loops around the origin.

Step by step solution

01

Understand the Hamiltonian

The Hamiltonian represents the total energy of the system and is typically given by \( \mathscr{H} = T + V \), where \( T \) is the kinetic energy and \( V \) is the potential energy. For a mass \( m \) moving along the x-axis, the kinetic energy \( T \) is \( \frac{p^2}{2m} \), where \( p \) is the momentum. The potential energy \( V \) due to a force \( F_x = -kx^3 \) can be found by integrating the force with respect to \( x \).
02

Compute the Potential Energy

Integrate the force \( F_x = -kx^3 \) with respect to \( x \) to find the potential energy \( V(x) \):\[ V(x) = \int -kx^3 \, dx = -\frac{k}{4}x^4 + C \]Assuming the integration constant \( C = 0 \) for simplicity, we have:\[ V(x) = -\frac{k}{4}x^4 \].
03

Write the Hamiltonian Expression

Combine the kinetic and potential energy expressions to formulate the Hamiltonian:\[ \mathscr{H}(x,p) = \frac{p^2}{2m} - \frac{k}{4}x^4 \].This expression represents the energy of the system in terms of the position \( x \) and momentum \( p \).
04

Analyze the Phase Space

Phase space is a graphical representation of all possible states of a system with position and momentum as coordinates. In this case, \( x \) is the position and \( p \) is the momentum. The phase space orbits can be visualized by holding the Hamiltonian constant and plotting \( p \) versus \( x \).
05

Sketch the Phase-Space Orbits

For a fixed energy level, the phase space orbits correspond to curves derived from the equation:\[ \frac{p^2}{2m} - \frac{k}{4}x^4 = E \] Rearranging gives:\[ p^2 = 2m \left(E + \frac{k}{4}x^4 \right) \].Plotting \( p \) versus \( x \) results in closed loops, resembling orbits around the origin, demonstrating how the state of the system evolves over time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Energy
Potential energy is a key concept in understanding how forces influence movement and interaction. It is stored energy that has the potential to do work, depending only on the position in space rather than the specific trajectory taken to get there.
Imagine potential energy like a stretched rubber band that stores energy because of its shape or position. When released, the stored energy causes movement.In the context of our exercise, we consider a particle experiencing a force in one dimension according to the equation \( F_x = -kx^3 \). The negative sign indicates this is a restoring force, pulling back towards equilibrium. To find the potential energy \( V(x) \), we integrate the force across distance:
  • Potential Energy Formula: \( V(x) = -\frac{k}{4}x^4 \)
This function shows that potential energy depends on \( x^4 \). As \( x \) increases or decreases from zero, the potential energy becomes more negative, indicating that the system can release this energy to perform work.
Kinetic Energy
Kinetic energy is the energy of motion. Think about objects rolling, flying, or simply moving over time - they all possess kinetic energy. It's proportional to mass and the square of velocity, showcasing how both mass and speed influence the energy a system can have.
For a particle confined along the x-axis, its kinetic energy can be described using momentum \( p \), where momentum links speed with mass. The formula for kinetic energy \( T \) becomes:
  • Kinetic Energy Formula: \( T = \frac{p^2}{2m} \)
Here, \( p^2/2m \) signifies that kinetic energy increases with the square of momentum. This relationship is crucial because it allows us to express energy in terms of variables (momentum and position) that align with Hamiltonian mechanics.Combining kinetic and potential energies helps us understand the full dynamics of a system, calculated through the Hamiltonian. Both energies are parts of the total energy a system possesses, illustrating how an object can convert from potential to kinetic states and vice versa, influencing its present and future states.
Phase Space
Phase space is a fundamental concept in Hamiltonian mechanics, serving as an abstract representation of all possible states of a system. Each point in phase space is defined by a set of coordinates, typically position \( x \) and momentum \( p \) here, showing the system's state at any given time.
Imagine phase space as a landscape of mountains and valleys - where the position marks the landscape points and momentum represents movement across this landscape.For mechanical systems, like a particle on the x-axis, analyzing phase space involves plotting \( p \) against \( x \). By keeping the Hamiltonian \( \mathscr{H}(x, p) \) constant, we visualize phase space orbits:
  • These orbits reflect system states over time related to specific energy levels.
  • Creating curves or loops shows the dynamic trajectory, akin to tracing a journey through this abstract landscape.
From our exercise, orbits emerge from the energy equation \( \frac{p^2}{2m} - \frac{k}{4}x^4 = E \), showing closed loops that describe how a system evolves with time. These phase space orbits help us understand not only the state transitions but also stability and periodicity in the system behaviors.

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Most popular questions from this chapter

Evaluate the three-dimensional divergence \(\nabla\). \(\mathbf{v}\) for each of the following vectors: \((\mathbf{a}) \mathbf{v}=k \hat{\mathbf{x}}\) (b) \(\mathbf{v}=k x \hat{\mathbf{x}},(\mathbf{c}) \mathbf{v}=k y \hat{\mathbf{x}} .\) We know that \(\mathbf{\nabla} \cdot \mathbf{v}\) represents the net outward flow associated with \(\mathbf{v} .\) In those cases where you found \(\nabla \cdot \mathbf{v}=0,\) make a simple sketch to illustrate that the outward flow is zero; in those cases where you found \(\nabla \cdot \mathbf{v} \neq 0,\) make a sketch to show why and whether the outflow is positive or negative.

The simple form \(\mathcal{H}=T+U\) is true only if your generalized coordinates are "natural" (relation betweeen generalized and underlying Cartesian coordinates is independent of time). If the generalized coordinates are not "natural," you must use the definition \(\mathcal{H}=\sum p_{i} \dot{q}_{i}-\mathcal{L} .\) To illustrate this point, consider the following: Two children are playing catch inside a railroad car that is moving with varying speed \(V\) along a straight horizontal track. For generalized coordinates you can use the position \((x, y, z)\) of the ball relative to a point fixed in the car, but in setting up the Hamiltonian you must use coordinates in an inertial frame \(-\) a frame fixed to the ground. Find the Hamiltonian for the ball and show that it is not equal to \(T+U\) (neither as measured in the car, nor as measured in the ground-based frame).

Consider a particle of mass \(m\) moving in two dimensions, subject to a force \(\mathbf{F}=-k x \hat{\mathbf{x}}+K \hat{\mathbf{y}}\) where \(k\) and \(K\) are positive constants. Write down the Hamiltonian and Hamilton's equations, using \(x\) and \(y\) as generalized coordinates. Solve the latter and describe the motion.

In the Lagrangian formalism, a coordinate \(q_{i}\) is ignorable if \(\partial \mathcal{L} / \partial q_{i}=0 ;\) that is, if \(\mathcal{L}\) is independent of \(q_{i}\). This guarantees that the momentum \(p_{i}\) is constant. In the Hamiltonian approach, we say that \(q_{i}\) is ignorable if \(\mathcal{H}\) is independent of \(q_{i}\), and this too guarantees \(p_{i}\) is constant. These two conditions must be the same, since the result " \(p_{i}=\) const" is the same either way. Prove directly that this is so, as follows: (a) For a system with one degree of freedom, prove that \(\partial \mathcal{H} / \partial q=-\partial \mathcal{L} / \partial q\) starting from the expression (13.14) for the Hamiltonian. This establishes that \(\partial \mathcal{H} / \partial q=0\) if and only if \(\partial \mathcal{L} / \partial q=0 .\) (b) For a system with \(n\) degrees of freedom, prove that \(\partial \mathcal{H} / \partial q_{i}=-\partial \mathcal{L} / \partial q_{i}\) starting from the expression (13.24).

Find the Lagrangian, the generalized momentum, and the Hamiltonian for a free particle (no forces at all) confined to move along the \(x\) axis. (Use \(x\) as your generalized coordinate.) Find and solve Hamilton's equations.

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