Suppose that you have found three independent principal axes (directions
\(\mathbf{e}_{1}, \mathbf{e}_{2}, \mathbf{e}_{3}\) ) and corresponding principal
moments \(\lambda_{1}, \lambda_{2}, \lambda_{3}\) of a rigid body whose moment
of inertia tensor \(\mathbf{I}\) (not diagonal) you had calculated. (You may
assume, what is actually fairly easy to prove, that all of the quantities
concerned are real.) (a) Prove that if \(\lambda_{i} \neq \lambda_{j}\) then it
is automatically the case that \(\mathbf{e}_{i} \cdot \mathbf{e}_{j}=0\) (It may
help to introduce a notation that distinguishes between vectors and matrices.
For example, you could use an underline to indicate a matrix, so that
\(\underline{\mathbf{a}}\) is the \(3 \times 1\) matrix that represents the vector
a, and the vector scalar product a \(\cdot \mathbf{b}\) is the same as the
matrix product \(\tilde{\mathbf{a}} \mathbf{b}\) or \(\underline{\mathbf{b}}\) a.
Then consider the number \(\tilde{\mathbf{e}}_{i} \mathbf{I} \mathbf{e}_{j},\)
which can be evaluated in two ways using the fact that both \(\mathbf{e}_{i}\)
and \(\mathbf{e}_{j}\) are eigenvectors
of I.) (b) Use the result of part (a) to show that if the three principal
moments are all different, then the directions of three principal axes are
uniquely determined. (c) Prove that if two of the principal moments are equal,
\(\lambda_{1}=\lambda_{2}\) say, then any direction in the plane of
\(\mathbf{e}_{1}\) and \(\mathbf{e}_{2}\) is also a principal axis with the same
principal moment. In other words, when \(\lambda_{1}=\lambda_{2}\) the
corresponding principal axes are not uniquely determined. (d) Prove that if
all three principal moments are equal, then any axis is a principal axis with
the same principal moment.