Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The sun is the only star whose size we can easily measure directly; astronomers therefore estimate the sizes of other stars using Stefan's law.

(a) The spectrum of Sirius A, plotted as a function of energy, peaks at a photon energy of2.4eV, while Sirius A is approximately 24times as luminous as the sun. How does the radius of Sirius A compare to the sun's radius?

(b) Sirius B, the companion of Sirius A (see Figure 7.12), is only role="math" localid="1647765883396" 3%as luminous as the sun. Its spectrum, plotted as a function of energy, peaks at about7eV. How does its radius compare to that of the sun?

(c) The spectrum of the star Betelgeuse, plotted as a function of energy, peaks at a photon energy of 0.8eV, while Betelgeuse is approximately10,000times as luminous as the sun. How does the radius of Betelgeuse compare to the sun's radius? Why is Betelgeuse called a "red supergiant"?

Short Answer

Expert verified

(a) . The radius of Sirius A is 1.69(In units of suns radius).

(b) . The radius of Sirius Bis0.007.

(c) .The radius of Betelgeuseis310.

Step by step solution

01

Step 1. Given information

The formula used is R=LT4to calculate the desired result.

02

Step 2. Calculating the radius of Sirius A  

The surface temperature of SiriusAis given by

2.4eV1.41eV=1.702

role="math" localid="1647766605943" So the radius of Sirius A shouldis

role="math" localid="1647766683798" =24(1.70)4

=1.69(In units of suns radius)

The radius of Sirius A is1.69.

03

Step 3. Calculating the radius of Sirius B

The surface temperature of SiriusBis given by

7eV1.41eV=4.96

Whichis nearly five times the suns temperature, so the radius of Sirius B should be

R=LT4

=0.03(4.96)4

=0.007

As it is less than 1%of suns radius and just slightly smaller than the earth's radius. This result is in rough agreement with that of7.23(d) where we calculated that, one solar - mass white decay should have a radius first slightly larger than earth's.

04

Step 4. Calculating the radius of  Betelgeuse 

The surface temperature ofBetalgeuseis given by

(0.8eV)(1.41eV)=0.57

the radius of Betelgeuse will be

R=LT4

=10,000(0.57)4

=310

As the radius is larger than the radius of earths orbit, and nearly as large as the orbit of mass. Super giant is certainly an approximate term. As for "red" the spectrum of Betelgeuse is certainly redder than the sun, due to its lower temperature of 3300K which makes its spectrum peak well into the infrared and fall of considerably at the blue end of the visible range. But this temperature is still slightly hotter than the filament of an incandescent bulb, so the color of Betelgeuse shouldn't be any redder than that of incandescent light, "yellow-orange' would be a more accurate description.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sometimes it is useful to know the free energy of a photon gas.

(a) Calculate the (Helmholtz) free energy directly from the definition

(Express the answer in terms of T' and V.)

(b) Check the formula S=-(โˆ‚F/โˆ‚T)Vfor this system.

(c) Differentiate F with respect to V to obtain the pressure of a photon gas. Check that your result agrees with that of the previous problem.

(d) A more interesting way to calculate F is to apply the formula F=-kTlnZ separately to each mode (that is, each effective oscillator), then sum over all modes. Carry out this calculation, to obtain

F=8ฯ€V(kT)4(hc)3โˆซ0โˆžx2ln1-e-xdx

Integrate by parts, and check that your answer agrees with part (a).

In Problem 7.28you found the density of states and the chemical potential for a two-dimensional Fermi gas. Calculate the heat capacity of this gas in the limit role="math" localid="1650099524353" kTโ‰ชฮตFยท Also show that the heat capacity has the expected behavior when kTโ‰ซฮตF. Sketch the heat capacity as a function of temperature.

If you have a computer system that can do numerical integrals, it's not particularly difficult to evaluate ฮผfor T>Tc.

(a) As usual when solving a problem on a computer, it's best to start by putting everything in terms dimensionless variables. So define t=T/Tc,c=ฮผ/kTc,andx=ฯต/kTc. Express the integral that defines ฮผ, equation N=โˆซ0โˆžg(ฯต)1e(ฯต-ฮผ)/kT-1dฯต, in terms of these variables, you should obtain the equation

2.315=โˆซ0โˆžxdxe(x-c)/t-1

(b) According to given figure , the correct value of cwhen T=2Tc, is approximately -0.8. Plug in these values and check that the equation above is approximately satisfied.

(c) Now vary ฮผ, holding Tfixed, to find the precise value of ฮผfor T=2Tc. Repeat for values ofT/Tcranging from 1.2up to 3.0, in increments of 0.2. Plot a graph of ฮผas a function of temperature.

Compute the quantum volume for an N2molecule at room temperature, and argue that a gas of such molecules at atmospheric pressure can be

treated using Boltzmann statistics. At about what temperature would quantum statistics become relevant for this system (keeping the density constant and pretending that the gas does not liquefy)?

For a system of fermions at room temperature, compute the probability of a single-particle state being occupied if its energy is

(a) 1eVless than ฮผ

(b) 0.01eVless than ฮผ

(c) equal to ฮผ

(d) 0.01eVgreater than ฮผ

(e) 1eVgreater thanฮผ

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free