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Suppose that an unsaturated air mass is rising and cooling at the dry adiabatic lapse rate found in problem 1.40. If the temperature at ground level is 25 C and the relative humidity there is 50%, at what altitude will this air mass become saturated so that condensation begins and a cloud forms (see Figure 5.18)? (Refer to the vapor pressure graph drawn in Problem 5.42)

Short Answer

Expert verified

The altitude at which air mass become saturated so that condensation begins and a cloud forms is 1.37 km

Step by step solution

01

Given information

(Refer table 5.11 and graph in problem 5.42)

At 25°Cand50%relative humidity, the partial pressure of water is 0.016 bar.

The temperature at which this partial pressure is in equilibrium with vapour pressure is13.8°C.

02

Estimating the height at which clouds will start forming.

From the dry adiabatic lapse rate for unsaturated air mass is

dTdZ=9.8°C/kmZ=1.14km

03

The height at which saturation begins.

The relation between pressure and height is

P(z)=Pe-z8.5

Substituting P=0.016 bar and z=1.14km

P(z) = 0.0014 bar

Using the graph in problem 5.42 we find this pressure is in equilibrium with vapour pressure at T=11.8°C

For condensation to occur the temperature should reduce to 9.8°C the air should rise a height.

04

determining the height

z=11.89.8(1.14)z=1.371.40km

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Most popular questions from this chapter

In this problem you will derive approximate formulas for the shapes of the phase boundary curves in diagrams such as Figures 5.31 and 5.32, assuming that both phases behave as ideal mixtures. For definiteness, suppose that the phases are liquid and gas.

(a) Show that in an ideal mixture of A and B, the chemical potential of species A can be written μA=μA°+kTln(1-x)where A is the chemical potential of pure A (at the same temperature and pressure) and x=NB/NA+NB. Derive a similar formula for the chemical potential of species B. Note that both formulas can be written for either the liquid phase or the gas phase.

(b) At any given temperature T, let x1 and xgbe the compositions of the liquid and gas phases that are in equilibrium with each other. By setting the appropriate chemical potentials equal to each other, show that x1and xg obey the equations =1-xl1-xg=eΔGA°/RTandxlxg=eΔGB°/RT and where ΔG°represents the change in G for the pure substance undergoing the phase change at temperature T.

(c) Over a limited range of temperatures, we can often assume that the main temperature dependence of ΔG°=ΔH°-TΔS°comes from the explicit T; both ΔH°andΔS°are approximately constant. With this simplification, rewrite the results of part (b) entirely in terms of ΔHA°,ΔHB° TA, and TB (eliminating ΔGandΔS). Solve for x1and xgas functions of T.

(d) Plot your results for the nitrogen-oxygen system. The latent heats of the pure substances areΔHN2°=5570J/molandΔHO2°=6820J/mol. Compare to the experimental diagram, Figure 5.31.

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