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In the previous section I derived the formula (F/V)T=-P. Explain why this formula makes intuitive sense, by discussing graphs of F vs. V with different slopes.

Short Answer

Expert verified

The equilibrium condition occurs when the slope of a curve of F verses V is equal.

Step by step solution

01

Given information

P=-FVT,N

02

Explanation

From thermodynamics Helmholtz free energy is given by

P=-FVT,N


Here, P is the pressure, F is Helmholtz free energy, V s the volume, T is the temperature and N is the number of molecules.


Write the expression for Helmholtz free energy: F=U-T S
Where, U is the internal energy and S is the entropy of the system.
The equilibrium state occurs when the energy of the system is the minimum and when the overall entropy is maximum.

For a given number of molecules and given temperature, the increase in the volume yields an increase in the entropy and decrease in the Helmholtz free energy.
Draw a graph to show the variation of F with V.
Conclusion:
So, the equilibrium condition occurs when the slope of a curve of F verses V is equal

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Most popular questions from this chapter

The density of ice is 917 kg/m*.

(a) Use the Clausius-Clapeyron relation to explain why the slope of the phase boundary between water and ice is negative.

(b) How much pressure would you have to put on an ice cube to make it melt at -1°C?

(c) ApprOximately how deep under a glacier would you have to be before the weight of the ice above gives the pressure you found in part (b)? (Note that the pressure can be greater at some locations, as where the glacier flows over a protruding rock.)

(d) Make a rough estimate of the pressure under the blade of an ice skate, and calculate the melting temperature of ice at this pressure. Some authors have claimed that skaters glide with very little friction because the increased pressure under the blade melts the ice to create a thin layer of water. What do you think of this explanation?

Below 0.3 K the slope of the °He solid-liquid phase boundary is negative (see Figure 5.13).

(a) Which phase, solid or liquid, is more dense? Which phase has more entropy (per mole)? Explain your reasoning carefully.

(b) Use the third law of thermodynamics to argue that the slope of the phase boundary must go to zero at T = 0. (Note that the *He solid-liquid phase boundary is essentially horizontal below 1 K.)

(c) Suppose that you compress liquid *He adiabatically until it becomes a solid. If the temperature just before the phase change is 0.1 K, will the temperature after the phase change be higher or lower? Explain your reasoning carefully.

The formula for CP-CV derived in the previous problem can also be derived starting with the definitions of these quantities in terms of U and H. Do so. Most of the derivation is very similar, but at one point you need to use the relation P=-(F/V)T.

Is heat capacity (C) extensive or intensive? What about specific heat (c) ? Explain briefly.

Figure 5.35 (left) shows the free energy curves at one particular temperature for a two-component system that has three possible solid phases (crystal structures), one of essentially pure A, one of essentially pure B, and one of intermediate composition. Draw tangent lines to determine which phases are present at which values of x. To determine qualitatively what happens at other temperatures, you can simply shift the liquid free energy curve up or down (since the entropy of the liquid is larger than that of any solid). Do so, and construct a qualitative phase diagram for this system. You should find two eutectic points. Examples of systems with this behaviour include water + ethylene glycol and tin - magnesium.

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