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A milk processor monitors the number of bacteria per milliliter in raw milk received at the factory. A random sample of 10one-milliliter specimens of milk supplied by one producer gives the following data:

Construct and interpret a 90% confidence interval for the population mean μ.

Short Answer

Expert verified

The confidence interval is(4794.4,5105.6)

Step by step solution

01

Step 1:Given information

The data is

02

Step 2:Calculation

The formula to compute the confidence interval is:

x¯-ta2,n-1×sn<μ<x¯+ta2,n-1×sn

Follow the provided steps of Minitab to compute the required confidence interval:

1. Enterthe data set in Minitab sheet.

2. Click on Stat > Basic Statistics > 1-Samplet

3. Select Samplein column.

4. Click on options and enter 90%in confidence level.

5. Click OK.

The obtained output is:

\

Hence, the required confidence interval is(4794.4,5105.6)

Therefore,

The obtained confidence interval shows that there is90% probability that the mean number of bacteria per millimeter in raw milk lies between 4794.4 and 5105.6.

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Most popular questions from this chapter

The standardized test statistic for a test of H0:p=0.4versus Ha:pnotequalto0.4isz=2.43This test is

a. not significant at either α=0.05or α=0.01

b. significant at α=0.05but not atα=0.01

c. significant atα=0.01but not at α=0.05

d. significant at both α=0.05andα=0.01

e. inconclusive because we don’t know the value of p^

Side effects A drug manufacturer claims that less than 10%of patients who take its new drug for treating Alzheimer’s disease will experience nausea. To test this claim, researchers conduct an experiment. They give the new drug to a random sample of 300out of 5000Alzheimer’s patients whose families have given informed consent for the patients to participate in the study. In all, 25of the subjects experience nausea.

a. Describe a Type I error and a Type II error in this setting, and give a possible

consequence of each.

b. Do these data provide convincing evidence for the drug manufacturer’s claim?

Tests and confidence intervals The P-value for a two-sided test of the null hypothesis H0:μ=15is0.03

a. Does the 99% confidence interval for μ include 15? Why or why not?

b. Does the 95% confidence interval for μ include 15? Why or why not?

After once again losing a football game to the archrival, a college’s alumni association conducted a survey to see if alumni were in favor of firing the coach. An SRS of 100 alumni from the population of all living alumni was taken, and 64 of the alumni in the sample were in favor of firing the coach. Suppose you wish to see if a majority of all living alumni is in favor of firing the coach. The appropriate standardized test statistic is

(a)z=0.64-0.50.64(0.36)100z=0.64-0.50.64(0.36)100

role="math" localid="1654432946823" (b)t=0.64-0.50.64(0.36)100t=0.64-0.50.64(0.36)100

(c)z=0.64-0.50.5(0.5)100z=0.64-0.50.5(0.5)100

(d)z=0.64-0.50.64(0.36)64z=0.64-0.50.64(0.36)64

(e)z=0.5-0.640.5(0.5)100z=0.5-0.640.5(0.5)100

Significance tests A test of Ho:p=0.5versus Ha:p>0.5based on

a sample of size 200yields the standardized test statistic z=2.19. Assume that the conditions for performing inference are met.

a. Find and interpret the P-value.

b. What conclusion would you make at the α=0.01 significance level? Would

your conclusion change if you used α=0.05 instead? Explain your reasoning.

c. Determine the value of p^= the sample proportion of successes.

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