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Checking conditions Refer to Exercise R9.1. Identify the appropriate test to

perform in each setting and show that the conditions for carrying out the test are met.

Short Answer

Expert verified

a. t-test for the mean for the one sample

b. ztest for the proportion for one sample

Step by step solution

01

Part (a) Step 1: Given information

When evaluating a claim about a proportion, use a one-sample z test, and when testing a claim about a mean, use a one-sample t-test.

02

Part (a) Step2: Calculation

Claim about a mean and therefore use a one-sample t-test for the mean.

Conditions

Random: The reason for my satisfaction is that the sample is a simple random sample.

Independent: The reason for this is that the sample of 48female graduates represents less than 10%of the total number of female graduates in the local high school.

Large sample: The reason for this is that the sample size of 48is more than 30and hence the sample size is enormous.

Even though all of the prerequisites are met, a hypothesis test for the population mean is appropriate.

03

Part (b) Step 1: Calculation

As a result of the claim concerning the proportion, a one-sample z-test for the proportion was used.

p=0.25n=80

Conditions

Random: The reason for my satisfaction is that the sample is a random sample.

Independent: The reason for this is that the sample of 80pupils at the school represents less than 10%of the total student population.

Normal: satisfied, the reason is that

np=80(0.25)=20n(1p)=80(10.25)=60

Both are at least 10

Despite the fact that all of the preceding conditions are met, it is appropriate to calculate the confidence interval for the population percentage p

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Most popular questions from this chapter

A company that manufactures classroom chairs for high school students

claims that the mean breaking strength of the chairs is 300 pounds. One of the chairs collapsed beneath a 220-pound student last week. You suspect that the manufacturer is exaggerating the breaking strength of the chairs, so you would like to perform a test of H0:μ=300Ha:μ<300where μ is the true mean breaking strength of this company’s classroom chairs.

a. The power of the test to detect that μ=294 based on a random sample of 30

chairs and a significance level of α=0.05 is 0.71. Interpret this value.

b. Find the probability of a Type I error and the probability of a Type II error for the test in part (a).

c. Describe two ways to increase the power of the test in part (a).

Bullies in middle school A media report claims that more than 75%of

middle school students engage in bullying behavior. A University of Illinois study on aggressive behavior surveyed a random sample of 558middle school students. When asked to describe their behavior in the last 30days, 445students admitted that they had engaged in physical aggression, social ridicule, teasing, name-calling, and issuing threats —all of which would be classified as bullying. Do these data provide convincing evidence at the α=0.05significance level that the media report’s claim is correct?

Experiments on learning in animals sometimes measure how long it takes mice to find their way through a maze. The mean time is 18 seconds for one particular maze. A researcher thinks that a loud noise will cause the mice to complete the maze faster. She measures how long each of 10 mice takes with a loud noise as stimulus. The appropriate hypotheses for the significance test are

a. H0:μ=18;Ha:μ18

b. H0:μ=18;Ha:μ>18

c. H0:μ<18;Ha:μ=18

d. H0:μ=18;Ha:μ<18

e. H0:x¯=18;Ha:x¯<18

pg559¯

No homework Refer to Exercises 1 and 9. What conclusion would you make at theα=0.05α=0.05level?

Don’t argue Refer to Exercises 2 and 12.

a. What conclusion would you make at the α=0.01 level?

b. Would your conclusion from part (a) change if a 5% significance level was used

instead? Explain your reasoning.

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