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Potato chips A company that makes potato chips requires each shipment of

potatoes to meet certain quality standards. If the company finds convincing evidence that more than 8%of the potatoes in the shipment have “blemishes,” the truck will be sent back to the supplier to get another load of potatoes. Otherwise, the entire truckload will be used to make potato chips. To make the decision, a supervisor will inspect a random sample of potatoes from the shipment. He will then perform a test of H0:p=0.08versus Ha:p>0.08, where p is the true proportion of potatoes with blemishes in a given truckload. The power of the test to detect that p=0.11, based on a random sample of 500 potatoes and significance level α=0.05, is 0.764Interpret this value.

Short Answer

Expert verified

There is sufficient evidence to favor the alternative hypothesis, that is, H0:p>0.08

Step by step solution

01

Given information

Hypothesized population proportion (p0)=0.08

Sample size (n)=500

Level of significance (α)=0.05

Power = 0.764

The null and alternative hypotheses are:

H0:p=0.08Ha:p>0.08
02

Concept

The likelihood of rejecting the null hypothesis if the alternative hypothesis is true is defined as the test's power.

03

Explanation

The test's power of 0.764 indicates that there is a 76.4 percent chance of concluding that there is adequate evidence to support the alternative hypothesis, H0:p>0.08

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Most popular questions from this chapter

Experiments on learning in animals sometimes measure how long it takes mice to find their way through a maze. The mean time is 18 seconds for one particular maze. A researcher thinks that a loud noise will cause the mice to complete the maze faster. She measures how long each of 10 mice takes with a loud noise as stimulus. The appropriate hypotheses for the significance test are

a. H0:μ=18;Ha:μ18

b. H0:μ=18;Ha:μ>18

c. H0:μ<18;Ha:μ=18

d. H0:μ=18;Ha:μ<18

e. H0:x¯=18;Ha:x¯<18

Making conclusions A student performs a test of H0:μ=12versus Ha:μ12

at the α=0.05significance level and gets a P-value of 0.01. The

student writes: “Because the P-value is small, we reject H0. The data prove that Hais true.” Explain what is wrong with this conclusion.

Ski jump When ski jumpers take off, the distance they fly varies considerably depending on their speed, skill, and wind conditions. Event organizers must position the landing area to allow for differences in the distances that the athletes fly. For a particular competition, the organizers estimate that the variation in distance flown by the athletes will be \(\sigma=10\) \(\sigma=10\) meters. An experienced jumper thinks that the organizers are underestimating the variation.

No homework? Refer to Exercise 1. The math teachers inspect the

homework assignments from a random sample of 50 students at the school. Only 68% of the students completed their math homework. A significance test yields a P-value of 0.1265.

a. Explain what it would mean for the null hypothesis to be true in this setting.

b. Interpret the P-value.

Fair coin? You want to determine if a coin is fair. So you toss it 10times and record the proportion of tosses that land “heads.” You would like to perform a test of H0:p=0.5versus Ha:p0.5, where p= the proportion of all tosses of the

coin that would land “heads.” Check if the conditions for performing the significance test are met.

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