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The standardized test statistic for a test of H0:p=0.4versus Ha:pnotequalto0.4isz=2.43This test is

a. not significant at either α=0.05or α=0.01

b. significant at α=0.05but not atα=0.01

c. significant atα=0.01but not at α=0.05

d. significant at both α=0.05andα=0.01

e. inconclusive because we don’t know the value of p^

Short Answer

Expert verified

The test is significant at α=0.05and α=0.01

The correct option is(b)

Step by step solution

01

Given information

z=2.43

Level of significance (α)=0.05/0.01

The null and alternative hypotheses are as follows:

H0:p=0.4Ha:pisnotequalto0.4

02

The objective is to find the test statistics values at which test is significant 

The -value can be computed as:

p-value=2×P(Z>z)=2×P(Z>2.43)=2×0.0075=0.0150

If the null hypothesis is rejected, the test will be significant.

If the p-value>αnull hypothesis is rejected.

p-value(0.0150)<α(0.05)=Reject the null hypothesis

p-value(0.0150)>α(0.01)=Fail to reject the null hypothesis

At α=0.05the test is considered significant.

Therefore, the correct option is(b)

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Most popular questions from this chapter

A company that manufactures classroom chairs for high school students

claims that the mean breaking strength of the chairs is 300 pounds. One of the chairs collapsed beneath a 220-pound student last week. You suspect that the manufacturer is exaggerating the breaking strength of the chairs, so you would like to perform a test of H0:μ=300Ha:μ<300where μ is the true mean breaking strength of this company’s classroom chairs.

a. The power of the test to detect that μ=294 based on a random sample of 30

chairs and a significance level of α=0.05 is 0.71. Interpret this value.

b. Find the probability of a Type I error and the probability of a Type II error for the test in part (a).

c. Describe two ways to increase the power of the test in part (a).

Cell-phone passwords A consumer organization suspects that less than half of parents know their child’s cell-phone password. The Pew Research Center asked a random sample of parents if they knew their child’s cell-phone password. Of the 1060parents surveyed, 551reported that they knew the password. Explain why it isn’t necessary to carry out a significance test in this setting.

Calculations and conclusions Refer to Exercise R9.1. Find the standardized test statistic and P-value in each setting, and make an appropriate conclusion.

Members of the city council want to know if a majority of city residents supports a 1%increase in the sales tax to fund road repairs. To investigate, they survey a random sample of 300city residents and use the results to test the following hypotheses:

H0:p=0.50

Ha:p>0.50

where pis the proportion of all city residents who support a 1% increase in the sales tax to fund road repairs.

A Type I error in the context of this study occurs if the city council

a. finds convincing evidence that a majority of residents supports the tax increase, when in reality there isn’t convincing evidence that a majority supports the increase.

b. finds convincing evidence that a majority of residents supports the tax increase, when in reality at most 50%of city residents support the increase.

c. finds convincing evidence that a majority of residents supports the tax increase, when in reality more than 50%of city residents do support the increase.

d. does not find convincing evidence that a majority of residents supports the tax increase, when in reality more than 50%of city residents do support the increase.

You are testing H0:μ=10against Ha:μ<10based on an SRS of20

observations from a Normal population. The t statistic is t=2.25

The P-value

a. falls between 0.01 and 0.02.

b. falls between 0.02 and 0.04.

c. falls between 0.04 and 0.05.

d. falls between 0.05 and 0.25.

e. is greater than 0.25.

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