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Opening a restaurant You are thinking about opening a restaurant and are

searching for a good location. From research you have done, you know that the mean income of those living near the restaurant must be over \(85,000to support the type of upscale restaurant you wish to open. You decide to take a simple random sample of 50people living near one potential location. Based on the mean income of this sample, you will perform a test of

H0:μ=\)85,000

Ha:μ>$85,000

where μis the true mean income in the population of people who live near the restaurant. Describe a Type I error and a Type II error in this setting, and give a possible consequence of each.

Short Answer

Expert verified

Once null hypothesis H0is true, type Ierror is rejecting null hypothesis H0.

Once null hypothesis H0is false, type IIerror fail to reject null hypothesis H0

Step by step solution

01

Given Information

It is given that n=50

H0:μ=$85,000

H1:μ>$85,000

02

Explanation

Once null hypothesis H0is true, type one error is rejecting null hypothesis H0

We have convincing proof that mean financial gain of these living close to restaurant is larger than 85000once mean financial gain of these living close to restaurant is actually 85000.

Double consequence is that opening restaurant in this area where financial gain of people is not enough and hence restaurant can depart of business.

One null hypothesis H0is false, type IIerror fail to reject H0

There is not enough convincing proof that mean financial gain of these living close to restaurant is larger than 85000, once mean financial gain of these living close to restaurant is actually 85000.

Double consequence is that not opening restaurant in this area where financial gain of people is large enough and hence it can miss profitable location.

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Most popular questions from this chapter

Cell-phone passwords A consumer organization suspects that less than half of parents know their child’s cell-phone password. The Pew Research Center asked a random sample of parents if they knew their child’s cell-phone password. Of the 1060parents surveyed, 551reported that they knew the password. Explain why it isn’t necessary to carry out a significance test in this setting.

A random sample of 100 likely voters in a small city produced 59 voters in favor of Candidate A. The observed value of the standardized test statistic for performing a test of H0:p=0.5H0:p=0.5versus Ha:p>0.5Ha:p>0.5

is which of the following?

a)z=0.59-0.50.59(0.41)100

b)z=0.59-0.50.5(0.5)100

c)z=0.5-0.590.59(0.41)100

d)z=0.5-0.590.5(0.5)100

e)z=0.59-0.5100

Powerful potatoes Refer to Exercise 85. Determine if each of the following

changes would increase or decrease the power of the test. Explain your answers.

a. Change the significance level to α=0.10

b. Take a random sample of 250 potatoes instead of 500 potatoes.

c. The true proportion is p=0.10 instead of p=0.11

The standardized test statistic for a test of H0:p=0.4versus Ha:pnotequalto0.4isz=2.43This test is

a. not significant at either α=0.05or α=0.01

b. significant at α=0.05but not atα=0.01

c. significant atα=0.01but not at α=0.05

d. significant at both α=0.05andα=0.01

e. inconclusive because we don’t know the value of p^

The reason we use t procedures instead of z procedures when carrying out a test about a population mean is that

a. z requires that the sample size be large.

b. z requires that you know the population standard deviation σ

c. z requires that the data come from a random sample.

d. z requires that the population distribution be Normal.

e. z can only be used for proportions.

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