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Heavy bread? The mean weight of loaves of bread produced at the bakery where you work is supposed to be 1pound. You are the supervisor of quality control at the bakery, and you are concerned that new employees are producing loaves that are too light. Suppose you weigh an SRS of bread loaves and find that the mean weight is 0.975pound.

a. State appropriate hypotheses for performing a significance test. Be sure to define the parameter of interest.

b. Explain why there is some evidence for the alternative hypothesis.

c. The P-value for the test in part (a) is 0.0806. Interpret the P-value.

d. What conclusion would you make at the α=0.01 significance level?

Short Answer

Expert verified

a. H0:μ=1and H1:μ<1

b. Sample mean of 0.975<1pound and mean is less than one pound.

c. 8.06%possibility that mean weight of random sample of broad leaves 0.975pound or more extreme, when mean weight is actually one pound.

d. There is no convincing proof that mean weight is less than one pound.

Step by step solution

01

Part (b) Step 1: Given Information

It is given that x¯=0.975

Claim is mean is less than 1.

02

Part (b) Step 2: Explanation

- The claim can be the null hypothesis or the alternative hypothesis.

- The null hypothesis statement is that population mean is equal to the value given in the claim.

- If the null hypothesis is the claim, then the alternative hypothesis statement is opposite of the null hypothesis.

H0:μ=1

H1:μ<1

Some proof for alternative hypothesis is there. It is because sample mean is less than one pound. It also corresponds with claim of alternative hypothesis that mean is less than one pound.

03

Part (a) Step 1: Given Information

Claim is mean is less than 1pound.

04

Part (a) Step 2: Explanation

Null Hypothesis: Population value is equal to value in claim.

H0:μ=1

The claim can be the null hypothesis or the alternative hypothesis. The null hypothesis is that the population mean is equal to the value given in the claim.

If the null hypothesis is the claim, then the alternative hypothesis statement will be the opposite of the null hypothesis.

H1:μ<1 (μ is mean weight of all bread loaves.)

05

Part (c) Step 1: Given Information

x¯=0.975

CLAIM: Mean is less than 1.

P=0.0806=8.06%

06

Part (c) Step 2: Explanation

As explained above

H0:μ=1

H1:μ<1

When null hypothesis is true, Pvalue is probability of getting the sample results or extreme results.

Therefore, 8.06% possibility that the mean weight of a simple random sample of bread loaves which is 0.975 pound or more extreme, when the mean weight of all bread loaves is actually one pound.

07

Part (d) Step 1: Given Information

It is given that x¯=0.975

P=0.0806=8.06%

α=0.01

CLAIM: Mean is less than one.

08

Part (d) Step 2: Explanation

From above:

H0:μ=1

H1:μ<1

Here, 0.0806>0.01Fail to ejectH0

So, there is no convincing proof that mean weight is less than one pound.

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Most popular questions from this chapter

Candy! A machine is supposed to fill bags with an average of 19.2 ounces of candy. The manager of the candy factory wants to be sure that the machine does not consistently underfill or overfill the bags. So the manager plans to conduct a significance test at the α=0.10significance level of

H0:μ=19.2Ha:μnotequalto19.2

where μ=the true mean amount of candy (in ounces) that the machine put in all bags filled that day. The manager takes a random sample of 75 bags of candy produced that day and weighs each bag. Check if the conditions for performing the test are met.

Packaging DVDs (6.2,5.3) A manufacturer of digital video discs (DVDs) wants to be sure that the DVDs will fit inside the plastic cases used as packaging. Both the cases and the DVDs are circular. According to the supplier, the diameters of the plastic cases vary Normally with mean μ=5.3inches and standard deviation σ=0.01inch. The DVD manufacturer produces DVDs with mean diameterμ=5.26inches. Their diameters follow a Normal distribution with σ=0.02inch.

a. Let X = the diameter of a randomly selected case and Y = the diameter of a randomly selected DVD. Describe the shape, center, and variability of the distribution of the random variable X−Y. What is the importance of this random variable to the DVD manufacturer?

b. Calculate the probability that a randomly selected DVD will fit inside a randomly selected case.

c. The production process runs in batches of 100 DVDs. If each of these DVDs is paired with a randomly chosen plastic case, find the probability that all the DVDs fit in their cases.

Making conclusions A student performs a test of H0:μ=12versus Ha:μ12

at the α=0.05significance level and gets a P-value of 0.01. The

student writes: “Because the P-value is small, we reject H0. The data prove that Hais true.” Explain what is wrong with this conclusion.

Walking to school A recent report claimed that 13%of students typically walk to school. DeAnna thinks that the proportion is higher than 0.13at her large elementary school. She surveys a random sample of 100students and finds that 17typically walk to school. DeAnna would like to carry out a test at the α=0.05significance level of H0:p=0.13versus Ha:p>0.13, where p= the true proportion of all students at her elementary school who typically walk to school. Check if the conditions for performing the significance test are met.

How much juice? Refer to Exercises 3 and 11 .

a. What conclusion would you make at the α=0.10α=0.10level?

b. Would your conclusion from part (a) change if a 5 \% significance level was used instead? Explain your reasoning.

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