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Attitudes Refer to Exercises 4 and 10 . What conclusion would you make at the α=0.05 level?

Short Answer

Expert verified

There is convincing evidence to help the claim that older students have better attitudes toward school, on average.

Step by step solution

01

Step 1:Given information

α=0.05level

02

Step 2:Explaination

P=0.0101

α=0.05

Given claim is mean is better than 115

The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis statement is that the population proportion is equal to the value given in the claim. If the null hypothesis is the claim, then the alternative hypothesis statement is the opposite of the null hypothesis.

H0:μ=115

H1:μ>115

If the P-value is smaller than the significance level , then reject the null hypothesis:

0.1265>0.05Fail to rejectH0

There is not enough convincing evidence to help the claim that less than 75%of the students at researcher's school finished their homework last night.

0.0101<0.05RejectH0

There is convincing evidence to help the claim that older students have better attitudes toward school, on average.

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Most popular questions from this chapter

Stating hypotheses

a. A change is made that should improve student satisfaction with the parking situation at a local high school. Before the change, 37%of students approve of the parking that's provided. The null hypothesis H0:p>0.37H0:p>0.37is tested against the alternative Ha: p=0.37Ha:p=0.37

b. A researcher suspects that the mean birth weights of babies whose mothers did not see a doctor before delivery is less than 3000 grams. The researcher states the hypotheses as

H0:x-=3000grams-5H0:x¯=3000grams

Ha: x-<3000grams Ha:x¯<3000grams

explain what's wrong with the stated hypotheses. Then give correct hypotheses.

A random sample of 100 likely voters in a small city produced 59 voters in favor of Candidate A. The observed value of the standardized test statistic for performing a test of H0:p=0.5H0:p=0.5versus Ha:p>0.5Ha:p>0.5

is which of the following?

a)z=0.59-0.50.59(0.41)100

b)z=0.59-0.50.5(0.5)100

c)z=0.5-0.590.59(0.41)100

d)z=0.5-0.590.5(0.5)100

e)z=0.59-0.5100

Experiments on learning in animals sometimes measure how long it takes mice to find their way through a maze. The mean time is 18 seconds for one particular maze. A researcher thinks that a loud noise will cause the mice to complete the maze faster. She measures how long each of 10 mice takes with a loud noise as stimulus. The appropriate hypotheses for the significance test are

a. H0:μ=18;Ha:μ18

b. H0:μ=18;Ha:μ>18

c. H0:μ<18;Ha:μ=18

d. H0:μ=18;Ha:μ<18

e. H0:x¯=18;Ha:x¯<18

Fire the coach!A college president says, “More than two-thirds of the alumni support my firing of Coach Boggs.” The president’s statement is based on 200emails he has received from alumni in the past three months. The college’s athletic director wants to perform a test of H0:p=2/3versus Ha:p>2/3, where p= the true proportion of the college’s alumni who favor firing the coach. Check if the conditions for performing the significance test are met.

Flu vaccine A drug company has developed a new vaccine for preventing the flu. The company claims that fewer than 5% of adults who use its vaccine will get the flu. To test the claim, researchers give the vaccine to a random sample of 1000 adults.

a. State appropriate hypotheses for testing the company’s claim. Be sure to define your parameter.

b. Describe a Type I error and a Type II error in this setting, and give the consequences Page Number: 615 of each.

c. Would you recommend a significance level of 0.01, 0.05, or 0.10 for this test? Justify your choice.

d. The power of the test to detect the fact that only 3% of adults who use this vaccine would develop flu using α=0.05 is 0.9437. Interpret this value.

e. Explain two ways that you could increase the power of the test from part (d).

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