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The mean amount of liquid in the bottles is 179.6ml and the standard deviation is 1.3ml. A significance test yields a P-value of 0.0589. Interpret the P-value.

Short Answer

Expert verified

There is a 5.89%possibility that the mean volume of liquid in a sample of 40bottles is 179.6milliliters or more extreme, when the mean volume of liquid of all bottles is180 milliliters.

Step by step solution

01

Step 1. Given information

P=0.0589=5.89%x¯=179.6s=1.3

Claim mean is180

02

Step 2. Explanation

The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis statement is that the population mean is equal to the value given in the claim. If the null hypothesis is the claim, then the alternative hypothesis statement is the opposite of the null hypothesis.

H0:μ=180Ha:μ180

The P-value is the probability of getting the value of the test static or a value more extreme, when the null hypothesis is true.

There is a 5.89%possibility that the mean volume of liquid in a sample of 40bottles is 179.6milliliters or more extreme, when the mean volume of liquid of all bottles is 180milliliters.

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Most popular questions from this chapter

Potato chips A company that makes potato chips requires each shipment of

potatoes to meet certain quality standards. If the company finds convincing evidence that more than 8%of the potatoes in the shipment have “blemishes,” the truck will be sent back to the supplier to get another load of potatoes. Otherwise, the entire truckload will be used to make potato chips. To make the decision, a supervisor will inspect a random sample of potatoes from the shipment. He will then perform a test of H0:p=0.08versus Ha:p>0.08, where p is the true proportion of potatoes with blemishes in a given truckload. The power of the test to detect that p=0.11, based on a random sample of 500 potatoes and significance level α=0.05, is 0.764Interpret this value.

An opinion poll asks a random sample of adults whether they favor banning ownership of handguns by private citizens. A commentator believes that more than half of all adults favor such a ban. The null and alternative hypotheses you would use to test this claim are

а.H0:p=0.5;Ha:p>0.5H0:p^=0.5;Ha:p^>0.5.

b. H0:p=0.5;Ha:p>0.5H0:p=0.5;Ha:p>0.5.

c. H0:p=0.5;Ha:p<0.5H0:p=0.5;Ha:p<0.5.

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e. H0:p>0.5;Ha:p=0.5H0:p>0.5;Ha:p=0.5.

In a test ofH0:p=0.4against Ha:p0.4, a random sample of size 100 yields a standardized test statistic of z=1.28. Which of the following is closest to the P-value for this test?

a. 0.90

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Potato power problems Refer to Exercises 85 and 87

a. Explain one disadvantage of using α=0.10 instead of α=0.05 when

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b. Explain one disadvantage of taking a random sample of 500 potatoes instead of 250 potatoes from the shipment.

Interpreting a P-value A student performs a test of H0:μ=100H0:μ=100versus Ha: μ>100Ha:μ>100and gets a P-value of 0.044.The student says, "There is a0.044 probability of getting the sample result I did by chance alone." Explain why the student's explanation is wrong.

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