Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Is your food safe? (8.1) “Do you feel confident or not confident that the food available at most grocery stores is safe to eat?” When a Gallup poll asked this question, 87% of the sample said they were confident.19 Gallup announced the poll’s margin of error for 95% confidence as ±3 percentage points. Which of the following sources of error are included in this margin of error? Explain your answer.

a. Gallup dialed landline telephone numbers at random and so missed all people without landline phones, including people whose only phone is a cell phone.

b. Some people whose numbers were chosen never answered the phone in several calls or answered but refused to participate in the poll.

c. There is chance variation in the random selection of telephone numbers.

Short Answer

Expert verified

Part (a) Not included.

Part (b) Not included.

Part (c) Included.

Step by step solution

01

Part (a) Step 1: Given information

The margin of error for 95 percent confidence in the poll was ±3 percentage points, according to Gallup.

02

Part (a) Step 2: Explanation

Only sampling error is included in the margin of error:

In addition to sampling errors, there are three types of errors that are not mentioned.

  • Selection bias can exclude a segment of the population
  • Response bias measurement can employ a technique that yields a value that differs significantly from the true value
  • Non-response bias occurs when there isn't enough information for everyone in the sample.

Because not everyone has a chance to be included in the sample, the error is choice bias, which, as we all know, is not contained within the margin of error.

03

Part (b) Step 1: Explanation

Only sampling error is included in the margin of error:

There are three types of errors that sampling error does not cover.

  • Selection bias will cause a portion of the population to be excluded.
  • Measurement or response bias can use a technique that produces a value that is completely different from the true value.
  • Non-response bias occurs when there isn't enough information for everyone in the sample.

Because not everyone in the sample responded, the error is non-response bias, which we all know is beyond the margin of error.

04

Part (c) Step 1: Explanation

Only sampling error is included in the margin of error:

There are three types of errors that sampling error does not cover.

  • Selection bias can exclude a portion of the population
  • Measurement of response bias can employ a technique that yields a value that differs significantly from the truth value
  • Non-response bias occurs when there isn't enough information for everyone in the sample.

The error is attributed to chance, which is lower than sampling error, therefore it is contained within the margin of error.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

AttitudesThe Survey of Study Habits and Attitudes (SSHA) is a psychological test that measures students' attitudes toward school and study habits. Scores range from 0 to 200 . Higher scores indicate better attitudes and study habits. The mean score for U.S. college students is about 115. A teacher suspects that older students have better attitudes toward school, on average. She gives the SSHA to an SRS of 45 of the over 1000 students at her college who are at least 30 years of age.

state appropriate hypotheses for performing a significance test. Be sure to define the parameter of interest

The reason we use t procedures instead of z procedures when carrying out a test about a population mean is that

a. z requires that the sample size be large.

b. z requires that you know the population standard deviation σ

c. z requires that the data come from a random sample.

d. z requires that the population distribution be Normal.

e. z can only be used for proportions.

Explaining confidence: Here is an explanation from a newspaper concerning one of its opinion polls. Explain what is wrong with the following statement.

For a poll of 1600 adults, the variation due to sampling error is no more than 3

percentage points either way. The error margin is said to be valid at the 95%

confidence level. This means that, if the same questions were repeated in 20 polls, the results of at least 19 surveys would be within 3 percentage points of the results of this survey.

Fast connection? How long does it take for a chunk of information to travel

from one server to another and back on the Internet? According to the site

internettrafficreport.com, the average response time is 200 milliseconds (about one-fifth of a second). Researchers wonder if this claim is true, so they collect data on response times (in milliseconds) for a random sample of 14 servers in Europe. A graph of the data reveals no strong skewness or outliers.

a. State an appropriate pair of hypotheses for a significance test in this setting. Be sure to define the parameter of interest.

b. Check conditions for performing the test in part (a).

c. The 95% confidence interval for the mean response time is 158.22 to 189.64

milliseconds. Based on this interval, what conclusion would you make for a test of the hypotheses in part (a) at the 5% significance level?

d. Do we have convincing evidence that the mean response time of servers in the United States is different from 200 milliseconds? Justify your answer.

Jump around Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was 15 inches. They wondered if the average vertical jump of students at their school differed from 15 inches, so they obtained a list of student names and selected a random sample of 20 students. After contacting these students several times, they finally convinced them to allow their vertical jumps to be measured. Here are the data (in inches):

Do these data provide convincing evidence at the α=0.10 level that the average vertical jump of students at this school differs from 15 inches?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free