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A researcher initially plans to take an SRS of size 160 from a certain population and calculate the sample mean x-x¯. Later, the researcher decides to increase the sample size so that the standard deviation of the sampling distribution of x-x¯will be half as big as when using a sample size of 160 . What sample size should the researcher use?

a. 40

b. 80

c. 320

d. 640

e. There is not enough information to determine the sample size.

Short Answer

Expert verified

(d). The sample size should the researcher is 640

Step by step solution

01

Given Information

Initially, a researcher intends to collect an SRS of size 160 from a specific demographic.

02

Explanation for correct option

The initial sample size was 160 people.

σx¯=σn

to reduce the standard deviation by half

σx¯2=12×σn=σ2n=σ22n=σ4n

In the equation of the standard deviation, the sample size n is replaced with 4 n, implying that the sample quadruples in size. n was the initial sample size. The sample with a standard deviation half as large

4n=4(160)=640

Hence, the correct option is (d)

03

Explanation for incorrect option

a. 40 is not the answer.

b. 80 is not the answer.

c. 320 is not the answer.

e. There is not enough information to determine the sample size is not the answer.

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Most popular questions from this chapter

Birth weights Researchers in Norway analyzed data on the birth weights of 400,000 newborns over a 6-year period. The distribution of birth weights is approximately Normal with a mean of 3668 grams and a standard deviation of 511 grams.

a. Sketch a graph that displays the distribution of birth weights for this population.

b. Sketch a possible graph of the distribution of birth weights for an SRS of size $5 . Calculate the range for this sample.

In this population, the range (Maximum - Minimum) of birth weights is 3417 grams. We technology to take 500 SRSs of size n=5n=5and calculate the range (Maximum Minimum) for each sample. The dotplot shows the results.

The mean of this distribution (don’t try to find it) will be

a. very close to the median.

b. greater than the median.

c. less than the median.

d. You can’t say, because the distribution isn’t symmetric.

e. You can’t say, because the distribution isn’t Normal.

IQ tests The Wechsler Adult Intelligence Scale (WAIS) is a common IQ test for adults. The distribution of WAIS scores for persons over 16 years of age is approximately Normal with mean 100 and standard deviation $15 .

a. What is the probability that a randomly chosen individual has a WAIS score of 105 or greater?

b. Find the mean and standard deviation of the sampling distribution of the average WAIS score x-x¯for an SRS of 60 people. Interpret the standard deviation.

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d. Would your answers to any of parts (a), (b), or (c) be affected if the distribution of WAIS scores in the adult population was distinctly non-Normal? Explain your reasoning.

The manufacturer of a certain brand of aluminum foil claims that the amount of foil on each roll follows a Normal distribution with a mean of 250 square feet (ft2 ) and a standard deviation of 2 ft2 . To test this claim, a restaurant randomly selects 10 rolls of this aluminum foil and carefully measures the mean area to bex=249.6ft2.

a. Find the probability that the sample mean area is 249.6ft2or less if the manufacturer’s claim is true.

b. Based on your answer to part (a), is there convincing evidence that the company is overstating the average area of its aluminum foil rolls?

10%Why is it important to check the 10 % condition before calculating probabilities involving localid="1654670795605">x-?

a. To reduce the variability of the sampling distribution of x-x¯

b. To ensure that the distribution of x-x¯is approximately Normal

c. To ensure that we can generalize the results to a larger population

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e. To ensure that the observations in the sample are close to independent

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