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Sample minimums List all 10possible SRSs of size n=3, calculate the minimum quiz score for each sample, and display the sampling distribution of the sample minimum on a dotplot.

Short Answer

Expert verified

The minimum sampling :

Sample of size 3
Sample Mean
Abigail - Bobby - Carlos
5
Abigail - Bobby - DeAnna
5
Abigail - Bobby - emily
5
Abigail - Carlos - DeAnna
7
Abigail - Carlos - Emily
9
Abigail - DeAnna - Emily
7
Bobby - Carlos - DeAnna
5
Bobby - Carlos - Emily
5
Bobby - DeAnna - Emily
5
Carlos - DeAnna - Emily
7

The dotplot is given below:

Step by step solution

01

Given information

We need to find minimum quiz score for each sample, and display the sampling distribution of the sample minimum on a dotplot for given table

Name
Gender
Quiz score
Abigail
Female
10
Bobby
Male
5
Carlos
Male
10
DeAnna
Female
7
Emily
Female
9
02

Simplify

As we know sample mean is minimum of the quiz score of sample.

Now, n=3, therefore,

Sample of size 3
Sample mean
Abigail - Bobby -Carlos
Min(10,5,10)=5
Abigail - Bobby - DeAnna
Min(10,5,7)=5
Abigail - Bobby - Emily
Min(10,5,9)=5
Abigail - Carlos - DeAnna
Min(10,10,7)=7
Abigail - Carlos - Emily
Min(10,10,9)=9
Abigail - DeAnna - Emily
Min(10,7,9)=7
Bobby - Carlos - DeAnna
Min(5,10,7)=5
Bobby - Carlos - Emily
Min(5,10,9)=5
Bobby - DeAnna - Emily
Min(5,7,9)=5
Carlos - DeAnna - Emily
Min(10,7,9)=7

A dot plot is a graph that shows the distribution of numerical variables by using dots to represent values.
If a value appears more than once in a whole number, the dots are stacked one on top of the other, with the height of the column of dots representing the frequency of that value.

Now from the above table, dot plot will be :

From dot plot,

Centre is about 8.25

Minimum =6

Maximum =10

Range =4

The distribution is slightly negative of left skewed.

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Most popular questions from this chapter

Airline passengers get heavier In response to the increasing weight of airline passengers, the Federal Aviation Administration (FAA) told airlines to assume that passengers average 190 pounds in the summer, including clothes and carry-on baggage. But passengers vary, and the FAA did not specify a standard deviation. A reasonable standard deviation is 35 pounds. A commuter plane carries 30 passengers. Find the probability that the total weight of 30 randomly selected passengers exceeds 6000 pounds.

The distribution of scores on the mathematics part of the SAT exam in a recent year was approximately Normal with mean 515 and standard deviation 114 . Imagine choosing many SRSs of 100 students who took the exam and averaging their SAT Math scores. Which of the following are the mean and standard deviation of the sampling distribution of x-?x¯?

a. Mean =515,SD=114

b. Mean =515,SD=114/100SD=114/100

c. Mean role="math" localid="1654342976765" =515/100,SD=114/100

d. Mean role="math" localid="1654343050312" =515/100,SD=114/100SD=114/10

e. Cannot be determined without knowing the 100 scores.

A study of voting chose 663 registered voters at random shortly after an election. Of these, 72%said they had voted in the election. Election records show that only 56%of registered voters voted in the election. Which of the following statements is true?

a. 72%is a sample; 56%is a population.

b. 72%and 56%are both statistics.

c. 72%is a statistic and 56%is a parameter.

d. 72%is a parameter and 56%is a statistic.

e. 72%and 56%are both parameters.

An insurance company claims that in the entire population of homeowners, the mean annual loss from fire is and the standard deviation of the loss is σ=\(5000.The distribution of losses is strongly right-skewed: many policies have \)0loss, but a few have large losses. The company hopes to sell 1000 of these policies for \(300each.

a. Assuming that the company’s claim is true, what is the probability that the mean loss from fire is greater than \)300for an SRS of 1000 homeowners?

b. If the company wants to be 90% certain that the mean loss from fire in an SRS of 1000 homeowners is less than the amount it charges for the policy, how much should the company charge?

The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is 50\( and the standard deviation is 20\). The distribution is not Normal: many households pay a low rate as part of a bundle with phone or television service, but some pay much more for Internet only or for faster connections. 11 A sample survey asks an SRS of 50 households with Internet access how much they pay. Let x-x¯be the mean amount paid.

a. Explain why you can't determine the probability that the amount a randomly selected household pays for access to the Internet exceeds 55 .\(

b. What are the mean and standard deviation of the sampling distribution of x-x¯?

c. What is the shape of the sampling distribution of x-x¯? Justify your answer.

d. Find the probability that the average fee paid by the sample of households exceeds 55 .\)

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