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Every 17 years, swarms of cicadas emerge from the ground in the eastern United States, live for about six weeks, and then die. (There are several different “broods,” so we experience cicada eruptions more often than every 17 years.) There are so many cicadas that their dead bodies can serve as fertilizer and increase plant growth. In a study, a researcher added 10 dead cicadas under 39 randomly selected plants in a natural plot of American bellflowers on the forest floor, leaving other plants undisturbed. One of the response variables measured was the size of seeds produced by the plants. Here are the boxplots and summary statistics of seed mass (in milligrams) for 39 cicada plants and 33 undisturbed (control) plants:

a. Write a few sentences comparing the distributions of seed mass for the two groups of plants.

b. Based on the graphical displays, which distribution likely has the larger mean? Justify your answer.

c. Explain the purpose of the random assignment in this study.

d. Name one benefit and one drawback of only using American bellflowers in the study

Short Answer

Expert verified

a. Cicada plants are skewed, with the same centre and a wider dispersion.

b. The graphical representations larger Cicada plant group is most likely responsible for the dispersion.

c. In experiments, researchers modify an independent variable while controlling for other variables to see how it affects a dependent variable.

d. 39 Plants in a natural plot of American bellflowers on the forest floor were chosen at random.

Step by step solution

01

Part (a) Step 1: Given Information

The given graph is

02

Part (a) Step 2: According to the question

The cicada plant distribution appears to be sloped to the right, whereas the control plant distribution appears to be tilted to the left.

For both distributions, the median would be the same, but the mean for Cicada Plants would be substantially higher.

The box plot is narrower than the cicada plants, which have a wider spread.

Because neither distribution appears to feature outliers, there are no 'x's in the box plots.

03

Part (b) Step 1: Given information

The given table is and the graph is

04

Part (b) Step 2: Calculation

In component (a), it was determined that the control plants group comprised more biassed. The mean in the control plants distribution is too much influenced by the left-skewed, and because a left-skewed distribution contains abnormally small values, these small values will decrease the mean, resulting in the control plants group's mean being lower than the cicada plants group's mean.

05

Part (c) Step 1: Given Information

The given table and graph is

06

Part (c) Step 2: According to question

The random group assignments ensure that the two groups are as similar as possible before to the experiment, as well as that the findings of the experiment are due to the treatments.

07

Part (d) Step 1: Given Information

The given table and the given graph is

08

Part (d) Step 2: According to the given question

Because all flowers will be of the same type, the variations between the treatment and control groups will be minimal.

One disadvantage is that you will only have data for one type of flower, so the experiment results will not be applicable to other flowers.

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Most popular questions from this chapter

Warm turkey Tom is cooking a large turkey breast for a holiday meal. He wants to be sure that the turkey is safe to eat, which requires a minimum internal temperature of 165°FTom uses a thermometer to measure the temperature of the turkey meat at four randomly chosen points. The minimum reading is 170°F

identify the population, the parameter, the sample, and the statistic.

Iced tea On Tuesday, the bottles of Arizona Iced Tea filled in a plant were supposed to contain an average of 20ounces of iced tea. Quality control inspectors selected 50bottles at random from the day’s production. These bottles contained an average of 19.6 ounces of iced tea. Identify the population, the parameter, the sample, and the statistic.


On one episode of his show, a radio show host encouraged his listeners to visit his website and vote in a poll about proposed tax increases. Of the 4821 people who vote, 4277 are against the proposed increases. To which of the following populations should the results of this poll be generalized?

a. All people who have ever listened to this show

b. All people who listened to this episode of the show

c. All people who visited the show host's website

d. All people who voted in the poll

e. All people who voted against the proposed increases

Social scientists are interested in the association between high school graduation rate (HSGR, measured as a percent) and the percent of U.S. families living in poverty (POV). Data were collected from all 50 states and the District of Columbia, and a regression analysis was conducted.

The resulting least-squares regression line is given by POV=59.2-0.620(HSGR) POV^=59.2-0.620(HSGR) with r2=0.802r2=0.802. Based on the information, which of the following is the best interpretation for the slope of the least-squares regression line?

a. For each 1% increase in the graduation rate, the percent of families living in poverty is predicted to decrease by approximately 0.896 .

b. For each 1 % increase in the graduation rate, the percent of families living in poverty is predicted to decrease by approximately 0.802.

c. For each 1 % increase in the graduation rate, the percent of families living in poverty is predicted to decrease by approximately 0.620.

d. For each 1 % increase in the percent of families living in poverty, the graduation rate is predicted to decrease by approximately 0.802.

e. For each 1 % increase in the percent of families living in poverty, the graduation rate is predicted to decrease by approximately 0.620.

The Gallup Poll has decided to increase the size of its random sample of voters from about 1500 people to about 4000 people right before an election. The poll is designed to estimate the proportion of voters who favor a new law banning smoking in public buildings. The effect of this increase is to

a. reduce the bias of the estimate.

b. increase the bias of the estimate.

c. reduce the variability of the estimate.

d. increase the variability of the estimate.

e. reduce the bias and variability of the estimate.

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