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A health worker is interested in determining if omega-3 fish oil can help reduce cholesterol in adults. She obtains permission to examine the health records of 200 people in a large medical clinic and classifies them according to whether or not they take omega-3 fish oil. She also obtains their latest cholesterol readings and finds that the mean cholesterol reading for those who are taking omega-3 fish oil is 18 points less than the mean for the group not taking omega-3 fish oil.

a. Is this an observational study or an experiment? Justify your answer.

b. Explain the concept of confounding in the context of this study and give one example of a variable that could be confounded with whether or not people take omega-3 fish oil.

c. Researchers find that the 18-point difference in the mean cholesterol readings of the two groups is statistically significant. Can they conclude that omega-3 fish oil is the cause? Why or why not?

Short Answer

Expert verified
  1. Observational study
  2. Two variables are confused when their effects on a response variable cannot be distinguished. The amount of exercise may be a complicating variable.
  3. No, due to the possibility of confounding variables.

Step by step solution

01

Part (a) Step 1: Given information

A health professional wants to know if omega-3 fish oil can help adults lower their cholesterol. She gets authorization to look through the medical records of 200 people at a large medical clinic and classify them based on whether or not they take omega-3 fish oil. She also collects their most recent cholesterol measurements and discovers that individuals who take omega-3 fish oil have a mean cholesterol reading that is 18 points lower than those who do not.

02

Part (a) Step 2: Explanation

An experiment purposely administers some therapy to participants in order to detect their responses. An observational research attempts to record information without disturbing the scene being observed. Because the data was based on health records, the individuals were not provided any treatment, and the researchers had no control over who took and who did not take omega-3 fish oil. The study is an observational study if no therapy was assigned.

03

Part (b) Step 1: Given information

A health professional wants to know if omega-3 fish oil can help adults lower their cholesterol. She gets authorization to look through the medical records of 200 people at a large medical clinic and classify them based on whether or not they take omega-3 fish oil. She also collects their most recent cholesterol measurements and discovers that individuals who take omega-3 fish oil have a mean cholesterol reading that is 18 points lower than those who do not.

04

Part (b)  Step 2: Explanation

The effects of two factors on the same response variable are said to be confused when they can't be distinguished. Omega-3 fish oil users may be more concerned about their health and, as a result, exercise more. Although the quantity of exercise has an impact on omega-3 fish oil levels, the amount of exercise has an impact on omega-3 fish oil levels.

05

Part (c) Step 1: Given information

A health professional wants to know if omega-3 fish oil can help adults lower their cholesterol. She gets authorization to look through the medical records of 200 people at a large medical clinic and classify them based on whether or not they take omega-3 fish oil. She also collects their most recent cholesterol measurements and discovers that individuals who take omega-3 fish oil have a mean cholesterol reading that is 18 points lower than those who do not.

06

Part (c) Step 2: Explanation

The study would be an observational study with possible confounding variables, according to the previous section's conclusion. As long as confounding variables exist, it is impossible to be 100 percent certain that omega-3 fish oil is the cause of the statistically significant difference.

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Most popular questions from this chapter

16.05A machine is designed to fill 16-ounce bottles of shampoo. When the machine is working properly, the amount poured into the bottles follows a Normal distribution with mean 16.05 ounces and standard deviation 0.1ounce. Assume that the machine is working properly. If 4 bottles are randomly selected and the number of ounces in each bottle is measured, then there is about a 95%probability that the sample mean will fall in which of the following intervals?

a. 16.05to 16.15ounces

b. 16.00to 16.10ounces

c. 15.95to role="math" localid="1654391534650" 16.15ounces

d. 15.90to 16.20ounces

e. 15.85to 16.25ounces

According to government data, 22%of American children under the age of 6 live in households with incomes less than the official poverty level. A study of learning in

early childhood chooses an SRS of300 children from one state and finds that pโˆงp^=.

a. Find the probability that at least 29%of the sample are from poverty-level households0.29households.

b. Based on your answer to part (a), is there convincing evidence that the percentage of children under the age of 6 living in households with incomes less than the official poverty level in this state is greater than the national value of 22%? Explain your reasoning.

Here are histograms of the values taken by three sample statistics in several hundred samples from the same population. The true value of the population parameter is marked with an arrow on each histogram.

Which statistic would provide the best estimate of the parameter? Justify your answer

You work for an advertising agency that is preparing a new television commercial to appeal to women. You have been asked to design an experiment to compare the effectiveness of three versions of the commercial. Each subject will be shown one of the three versions and then asked to reveal her attitude toward the product. You think there may be large differences in the responses of women who are employed and those who are not. Because of these differences, you should use

a. a block design, but not a matched pairs design.

b. a completely randomized design.

c. a matched pairs design.

d. a simple random sample.

e. a stratified random sample.

Tall girls? To see if the claim made in Exercise 12is true at their high school, an Ap Statistics class chooses an SRS of twenty 16-year-old females at the school and measures their heights. In their sample, the mean height is 64.7inches. Does this provide convincing evidence that 16-year-old females at this school are taller than 64inches, on average?

a. What is the evidence that the average height of all 16-year-old females at this school is greater than 64inches, on average?

b. Provide two explanations for the evidence described in part (a).

We used technology to simulate choosing 250SRSs of size n=20from a population of three hundred 16-year-old females whose heights follow a Normal distribution with mean localid="1654113150676" ฮผ=64inches and standard deviation ฮผ=2.5inches. The dotplot shows x=the sample mean height for each of the 250simulated samples.

c. There is one dot on the graph at 62.5. Explain what this value represents.

d. Would it be surprising to get a sample mean of x=64.7or larger in an SRS of size 20when ฮผ=64inches and ฯƒ=2.5inches? Justify your answer.

e. Based on your previous answers, is there convincing evidence that the average height of all 16-year-old females at this school is greater than 64inches? Explain your reasoning.

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