Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Geometric or not? Determine whether each of the following scenarios describes a geometric setting. If so, define an appropriate geometric random variable.

a. A popular brand of cereal puts a card bearing the image of 1 of 5 famous NASCAR drivers in each box. There is a 1/5chance that any particular driver's card ends up in any box of cereal. Buy boxes of the cereal until you have all 5 drivers' cards.

b. In a game of 4-Spot Keno, Lola picks 4 numbers from 1 to 80 . The casino randomly selects 20 winning numbers from 1 to 80 . Lola wins money if she picks 2 or more of the winning numbers. The probability that this happens is \(0.259\). Lola decides to keep playing games of 4-Spot Keno until she wins some money.

Short Answer

Expert verified

(a)No geometric distribution, the reason is that does not count until the first success and interested in five successes.

(b) the reason is that the two possible results are win money and do not win money, draws are independent and compute the number of draws until the first success and p=0.259.

Step by step solution

01

Part (a) Step 1: Given Information

The following examples describe whether or not a geometric setting exists. If so, define an appropriate geometric random variable.

02

Part (a) Step 2: Simplification

The geometric distribution of a random variable When a variable has two possible outcomes, each draw is independent of the previous ones. The variable computes the number of draws needed until the first success. Every draw has the same chance of winning.

There is no geometric distribution because it does not count until the first success and is only interested in five successes.

03

Part (b) Step 1: Given Information

The following examples describe whether or not a geometric setting exists. If so, define an appropriate geometric random variable.

04

Part (b) Step 2: Simplification

The geometric distribution of a random variable When a variable has two possible outcomes, each draw is independent of the previous ones. The variable computes the number of draws needed until the first success. Every draw has the same chance of winning.

Every draw has the same chance of winning.

The reason for this is that the two possible outcomes are win money and do not win money, drawings are independent, and the number of draws until the first success is computed.

p=0.259.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Housing in San Josรฉ How do rented housing units differ from units occupied by their owners? Here are the distributions of the number of rooms for owner-occupied units and renter-occupied units in San Josรฉ, California:

Let X= the number of rooms in a randomly selected owner-occupied unit and Y = the number of rooms in a randomly chosen renter-occupied unit.

(a) Here are histograms comparing the probability distributions of X and Y. Describe any differences you observe.

(b) Find the expected number of rooms for both types of housing unit. Explain why this difference makes sense.

(c) The standard deviations of the two random variables are ฯƒX=1.640and ฯƒY=1.308. Explain why this difference makes sense.

Kids and toys In an experiment on the behavior of young children, each subject is placed in an area with five toys. Past experiments have shown that the probability distribution of the number X of toys played with by a randomly selected subject is as follows:

Part (a). Write the event โ€œchild plays with 5 toysโ€ in terms of X. Then find its probability.

Part (b). Whatโ€™s the probability that a randomly selected subject plays with at most 3 toys?

Bag check Refer to Exercise 91 .

a. Calculate and interpret the mean of R.

b. Calculate and interpret the standard deviation of R.

The time X it takes Hattan to drive to work on a randomly selected day follows a distribution that is approximately Normal with mean 15 minutes and standard deviation 6.5 minutes. Once he parks his car in his reserved space, it takes 5 more minutes for him to walk to his office. Let T= the total time it takes Hattan to reach his office on a randomly selected day, so T=X+5. Describe the shape, center, and variability of the probability distribution of T.

Toothpaste Ken is traveling for his business. He has a new 0.85-ounce tube of toothpaste that's supposed to last him the whole trip. The amount of toothpaste Ken squeezes out of the tube each time he brushes varies according to a Normal distribution with mean 0.13ounces and standard deviation 0.02ounces. If Ken brushes his teeth six times during the trip, what's the probability that he'll use all the toothpaste in the tube? Follow the four-step process.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free