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Taking the train According to New Jersey Transit, the 8:00A.M. weekday train from Princeton to New York City has a 90%chance of arriving on time on a randomly selected day. Suppose this claim is true. Choose 6 days at random. Let localid="1654594369074" Y=the number of days on which the train arrives on time.

Short Answer

Expert verified

The given statement is true, because Y is followed by binomial distribution

Step by step solution

01

Given Informaiotn

The likelihood of success p=90%=0.90

The number trials conducted (n)=6

02

Simplification

The random variable Y satisfies the following requirements.

1. The likelihood of success, i.e., the probability of arriving on time, is fixed at 0.90.

2. The number of days is set.

3. Days are separate from one another.

4. There are two possible outcomes: trains arriving on time or not arriving on time.

Here, all of the binomial criteria are met. As a result, Y is said to follow the binomial distribution.

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Most popular questions from this chapter

Skee Ball Refer to Exercise 4. Find the mean of X. Interpret this value.

Benfordโ€™s law Faked numbers in tax returns, invoices, or expense account claims often display patterns that arenโ€™t present in legitimate records. Some patterns, like too many round numbers, are obvious and easily avoided by a clever crook. Others are more subtle. It is a striking fact that the first digits of numbers in legitimate records often follow a model known as Benfordโ€™s law. 4 Call the first digit of a randomly chosen legitimate record X for short. The probability distribution for X is shown here (note that a first digit cannot be 0).

Part (a.) A histogram of the probability distribution is shown. Describe its shape.

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Working outExercise 10 described a large sample survey that asked a sample of people aged 19 to 25 years, โ€œIn the past seven days, how many times did you go to an exercise or fitness center or work out?โ€ The response Y for a randomly selected survey respondent has the probability distribution shown here. From Exercise 10, E(Y)=1.03. Find the standard deviation of Y. Interpret this value.

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