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At the main campus, full-time students pay \(50 per unit. At the downtown campus, full-time students pay \)55 per unit. Find the mean of the difference D (Main − Downtown) in the number of units that the two randomly selected students take.

Short Answer

Expert verified

The difference's average isμD=0.35units

Step by step solution

01

Given information

X and Y are two random variables that are independent of each other.

Further X;

The mean is μX=732.50and standard deviation is σX=103

Finding Y:

The mean is μY=825 and standard deviation isσY=126.50

02

Calculations

We know that X is the amount spent on tuition at Main campus by a randomly picked student.

Y: the amount spent on tuition by a student at the Downtown campus who was chosen at random.

The full-time student on the main campus pays $ 50 per unit.

When the entire amount spent is divided by 50, we get the number of units.

Mean is a central measure, as we all know.

When each data value is multiplied by 50, the measure of centre should be multiplied by 50 as well.

Thus,

When we divide the total amount spent by 50, we get the number of units.

Mean is a central measure, as we all know.

When each data value is multiplied by 50, the measure of centre should be multiplied by 50 as well.

As a result, for the main campus,

μMain=μX50=732.5050=14.65units

At the moment, a full-time student at the downtown campus pays $ 55 per unit.

When the total money spent is divided by $55, we get the number of units.

Mean is a central measure, as we all know.

When every data value is multiplied by 55, the centre measure should also be multiplied by $55.

As a result, when it comes to the Downtown campus,

μDowntown=μY55=82555=15units

The mean of the difference between two random variables is equal to the difference between their means.

width="311">μD=μMaintown-Downtown=μMainμDowntown=14.6515=0.35units

On average, students at the Main campus take fewer 0.35units than students at the Downtown campus.

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