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Victoria parks her car at the same garage every time she goes to work. Because she stays at work for different lengths of time each day, the fee the parking garage charges on a randomly selected day is a random variable, G. The table gives the probability distribution of G.You can check that μG=\(14and σG=\)2.74.

In addition to the garage’s fee, the city charges a $3use tax each time Victoria parks her car. Let T=the total amount of money she pays on a randomly selected day.

a. Make a graph of the probability distribution of T. Describe its shape.

b. Find and interpret μT.

c. Calculate and interpret σT.

Short Answer

Expert verified

a. The distribution is not symmetric, with the tallest bars in the middle at X=18, a single peak with the highest likelihood, and the lowest bars at X=23, with the lowest probability.

b. When the constant value is added to each data point, the center of the distribution is enlarged by (μG+3) and the total amount is increased by $3, resulting in $17average money being randomly selected.

c. When a constant value is added to all data, it has no effect on the spread of the distribution, hence money for a random selection ranges on average $2.74about the mean =$17.

Step by step solution

01

Part(a) Step 1 : Given Information

Given table:

02

Part(a) Step 2 : Simplification

The city charges a $3use tax each time Victoria parks her car.

So,X=Y+3

The required graph is :

03

Part(b) Step 1 : Given Information

Given table :

04

Part(b) Step 2 : Simplification

Ystands for garage cost. $3must be paid in addition to the garage cost, bringing the total price to role="math" localid="1653997585789" $3

X=Y+3.

When the constant is added to each data value, the distribution's center is also enhanced by that constant value.

μT=μG+3=14+3Mr=17

05

Part(c) Step 1 : Given Information

Given table :

06

Part(c) Step 2 : Simplification

Ystands for garage cost. The garage fee must be paid in addition by $3, bringing the total price to $3.

X=Y+3

When you add the constant to every data value, the spread of the distribution does not change; it stays the same.

σx=σy=2.74

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Most popular questions from this chapter

Toothpaste Ken is traveling for his business. He has a new 0.85-ounce tube of toothpaste that's supposed to last him the whole trip. The amount of toothpaste Ken squeezes out of the tube each time he brushes varies according to a Normal distribution with mean 0.13ounces and standard deviation 0.02ounces. If Ken brushes his teeth six times during the trip, what's the probability that he'll use all the toothpaste in the tube? Follow the four-step process.

Quick, click! An Internet reaction time test asks subjects to click their mouse button as soon as a light flashes on the screen. The light is programmed to go on at a randomly selected time after the subject clicks “Start.” The density curve models the amount of time Y (in seconds) that the subject has to wait for the light to flash.

a) Find and interpret P(Y>3.75)

b) What is μY? Explain your answer.

c) Find the value of k that makes this statement true:P(Yk)=0.38

Get on the boat! Refer to Exercise 3. Find the mean of Y. Interpret this value.

Get on the boat! Refer to Exercise 3. Make a histogram of the probability distribution. Describe its shape.

Benford’s law and fraud

(a) Using the graph from Exercise 21, calculate the standard deviation σY. This gives us an idea of how much variation we’d expect in the employee’s expense records if he assumed that first digits from 1 to 9 were equally likely.

(b) The standard deviation of the first digits of randomly selected expense amounts that follow Benford’s law is σX=2.46. Would using standard deviations be a good way to detect fraud? Explain your answer.

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