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Get on the boat! A small ferry runs every half hour from one side of a large river to the other. The probability distribution for the random variable Y= money collected on a randomly selected ferry trip is shown here. From Exercise 7, μY=$19.35.

(a) Find the median of Y.

(b) Compare the mean and median. Explain why this relationship makes sense based on the probability distribution.

Short Answer

Expert verified

Part (a) $20.

Part (b) Distribution is left-skewed.

Step by step solution

01

Part (a) Step 1. Given information.

The given information is:

02

Part (a) Step 2. Find the median of Y. 

Money CollectedProbabilityCumulative Probability
00.020.02
50.050.07
100.080.15
150.160.31
200.270.58
250.421

The median will be the amount of money collected for the category with a cumulative probability of at least 0.5 and a probability of less than 0.5 for the prior category.

The $20 collected category has a cumulative probability of 0.58, while the $ 15 collected category has a cumulative probability of 0.31.

As a result, the median is set at $20.

03

Part (b) Step 1. Compare the mean and median.

The given mean is $19.35. $20 is the median that we calculated.

We can see that the mean is less than the median, indicating that the distribution is skewed to the left. This is because the mean is influenced by unusual values more strongly than the median, and thus there appear to be unusually small values in the distribution which are affecting the mean.

This is consistent with the conclusion we reached in the previous exercise about the form of the histogram.

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Most popular questions from this chapter

Exercises 21 and 22 examine how Benford’s law (Exercise 9) can be used to detect fraud.

Benford’s law and fraud A not-so-clever employee decided to fake his monthly expense report. He believed that the first digits of his expense amounts should be equally likely to be any of the numbers from 1 to 9. In that case, the first digit Yof a randomly selected expense amount would have the probability distribution shown in the histogram.

(a) What’s P(Y<6)? According to Benford’s law (see Exercise 9), what proportion of first digits in the employee’s expense amounts should be greater than 6? How could this information be used to detect a fake expense report?

(b) Explain why the mean of the random variable Yis located at the solid red line in the figure.

(c) According to Benford’s law, the expected value of the first digit is μX=3.441. Explain how this information could be used to detect a fake expense report.

Easy-start mower Refer to Exercise 92 .

a. Calculate and interpret the mean of T.

b. Calculate and interpret the standard deviation of T.

1-in-6 wins Alan decides to use a different strategy for the 1-in-6 wins game of Exercise 90¯. He keeps buying one 20 -ounce bottle of the soda at a time until he gets a winner.

a. Find the probability that he buys exactly 5 bottles.

b. Find the probability that he buys at most 6 bottles. Show your work.

Baby elk Biologists estimate that a randomly selected baby elk has a 44 % chance of surviving to adulthood. Assume this estimate is correct. Suppose researchers choose 7 baby elk at random to monitor. Let X= the number that survive to adulthood.

Victoria parks her car at the same garage every time she goes to work. Because she stays at work for different lengths of time each day, the fee the parking garage charges on a randomly selected day is a random variable, G. The table gives the probability distribution of G.You can check that μG=\(14and σG=\)2.74.

In addition to the garage’s fee, the city charges a $3use tax each time Victoria parks her car. Let T=the total amount of money she pays on a randomly selected day.

a. Make a graph of the probability distribution of T. Describe its shape.

b. Find and interpret μT.

c. Calculate and interpret σT.

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