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Chapter 5: R5.4 - Review Exercises (page 356)

What kind of vehicle? : Randomly select a new vehicle sold in the United States in a certain month. The probability distribution for the type of vehicle chosen is given here.

Vehicle TypePassenger carPickup TruckSUVCrossoverMinivan
Probability0.46
0.15
0.10
?
0.05

a. What is the probability that the vehicle is a crossover? How do you know?

b. Find the probability that vehicle is not an SUV or Minivan .

c. Given that the vehicle is not a passenger car, what is the probability that it is a pickup truck?

Short Answer

Expert verified

(a) The probability that vehicle is a crossover is 0.24.

(b) The probability vehicle is not an SUV or Minivan is 0.85.

(c) The probability vehicle is not a passenger car but a pickup car is0.15.

Step by step solution

01

Part(a) - Step 1 : Given Information

We are given different of different kind of vehicles and their probability of being chosen . We need to find the probability of crossover vehicle.

Vehicle TypePassenger carPickup TruckSUVCrossoverMinivan
Probability0.46
0.150.10 ?0.05
02

Part (a) - Step 2 : Explanation

Total probability of an event to completely occur is equal to 1.

Probability of all vehicles=1

Let probability of choosing crossover bex.

0.46+0.15+0.10+x+0.05=1

0.76+x=1

x=0.24

Probability of choosing crossover vehicle is0.24.

03

Part (b) - Step 1 : Given Information

We are given different of different kind of vehicles and their probability of being chosen . We need to find the probability that vehicle is not an SUV or Minivan .

04

Part (b) - Step 2 : Explanation

Probability of an event to completely occur is equal to 1.

Probability ( Vehicle is not an SUV or Minivan) =1-(Probability of choosing SUV +Probability of choosing Minivan).

Probability ( vehicle is not an SUV or Minivan) =1-(0.10+0.05)=1-0.15=0.85

05

Part (c) - Step 1 : Given Information

We are given different of different kind of vehicles and their probability of being chosen . We need to find that if vehicle is not a passenger car, what is the probability that it is a pickup truck .

06

Part (c) - Step 2 : Explanation

The probability if vehicle is not a passenger car, but is a pickup truck is given in the problem itself and is equal to 0.15

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Most popular questions from this chapter

Which one of the following is true about the events “Owner has a Chevy” and

“Owner’s truck has four-wheel drive”?

a. These two events are mutually exclusive and independent.

b. These two events are mutually exclusive, but not independent.

c. These two events are not mutually exclusive, but they are independent.

d. These two events are neither mutually exclusive nor independent.

e. These two events are mutually exclusive, but we do not have enough information to determine if they are independent.

2Drive to exercise : The two-way table summarizes the responses of 120 people to a survey in which they were asked, “Do you exercise for at least 30 minutes four or more times per week?” and “What kind of vehicle do you drive?”

ExerciseSedanSUVTruck
Yes251512
No202424

Suppose one person from this sample is randomly selected.

a. Find the probability that the person drives an SUV.

b. Find the probability that the person drives a sedan or exercises for at least 30 minutes four or more times per week.

c. Find the probability that the person does not drive a truck, given that she or he exercises for at least 30 minutes four or more times per week.

Lefties A website claims that 10%of U.S. adults are left-handed. A researcher believes that this figure is too low. She decides to test this claim by taking a random sample of 20U.S. adults and recording how many are left-handed. Four of the adults in the sample are left-handed. Does this result give convincing evidence that the website’s 10%claim is too low? To find out, we want to perform a simulation to estimate the probability of getting 4or more left-handed people in a random sample of size 20from a very large population in which 10%of the people are left-handed.

Let 00to 09indicate left-handed and 10to 99 represent right-handed. Move left to Page Number: 311right across a row in Table D. Each pair of digits represents one person. Keep going until you get20 different pairs of digits. Record how many people in the simulated sample are left-handed. Repeat this process many, many times. Find the proportion of trials in which4 or more people in the simulated sample were left-handed.

Double fault!A professional tennis player claims to get 90%of her second serves in. In a recent match, the player missed 5of her first 20second serves. Is this a surprising result if the player’s claim is true? Assume that the player has a 0.10probability of missing each second serve. We want to carry out a simulation to estimate the probability that she would miss 5or more of her first 20second serves.

a. Describe how to use a random number generator to perform one trial of the simulation. The dot plot displays the number of second serves missed by the player out of the first 20second serves in simulated matches.

b. Explain what the dot at 6represents.

c. Use the results of the simulation to estimate the probability that the player would miss 5or more of her first 20second serves in a match.

d. Is there convincing evidence that the player misses more than 10%of her second serves? Explain your answer.

What is the probability that the person owns a Dodge or has four-wheel drive?

a.20/80b.20/125c.80/125d.90/125e.110/125

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