Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A random sample of 415children from England and the United States who completed a survey in a recent year was selected. Each student’s country of origin was recorded along with which superpower they would most like to have: the ability to fly, ability to freeze time, invisibility, super strength, or telepathy (ability to read minds). The data are summarized in the two-way table.

Suppose we randomly select one of these students. Define events E: England, T: telepathy, and S: superstrength.

a. Find P(T|E).Interpret this value in context.

b. Given that the student did not choose superstrength, what’s the probability that this child is from England? Write your answer as a probability statement using correct symbols for the events.

Short Answer

Expert verified

Part (a) Probability for the child from England prefers Telepathy, P(T|E)=0.22

Part (b) Probability that the child from England did not choose superstrength,P(E|S)0.4839

Step by step solution

01

Part (a) Step 1. 

Data for superpowers in the two – way table:

02

Part (a) Step 2. Explanation

According to conditional probability,

P(B|A)=P(AB)P(A)=P(AandB)P(A)

We know

E: England

T: Telepathy

Note that

The information about 415children is provided in the table.

Thus,

The number of possible outcomes is 415.

Also note that

In the table, 200of the 415children are from England.

Thus,

The number of favorable outcomes is 200.

When the number of favorable outcomes is divided by the number of possible outcomes, we get the probability.

P(E)=NumberoffavorableoutcomesNumberofpossibleoutcomes=200415

Now,

Note that

In the table, 44of the 415children are from England and prefer Telepathy. In this case, the number of favorable outcomes is 44and number of possible outcomes is 415.

P(EandT)=NumberoffavorableoutcomesNumberofpossibleoutcomes=44415

Apply conditional probability:

P(E|T)=P(EandT)P(E)=44415200415=44200=1150=0.2=22%

Therefore,

Around 22%of the children from England prefer Telepathy and the probability for the child from England prefers Telepathy is 0.22.

03

Part (b) Step 1. Explanation

According to complement rule,

P(Ac)=P(notA)=1-P(A)

According to conditional probability,

P(B|A)=P(AB)P(A)=P(AandB)P(A)

We know

E: England

S: Superstrength

Note that

The information about 415children is provided in the table.

Thus,

The number of possible outcomes is 415.

Also note that

In the table, 43of the 415children from both the countries prefer superstrength.

Thus,

The number of favorable outcomes is 43.

When the number of favorable outcomes is divided by the number of possible outcomes, we get the probability.

P(S)=NumberoffavorableoutcomesNumberofpossibleoutcomes=43415

Apply complement rule:

P(Sc)=P(notS)=1-43415=372415

Now,

Note that

In the table, 20children from total 200children from England prefer Superstrength.

That means

Remaining 180children from total 200children from England do not prefer Superstrength.

In this case, the number of favorable outcomes is 180.

Since the total children from both the countries are 415.

Thus,

The number of possible outcomes is 415.

P(EandSc)=NumberoffavorableoutcomesNumberofpossibleoutcomes=180415

Apply conditional probability:

P(E|Sc)=P(EandSc)P(A)=180415372415=180372=15310.4839=48.39%

Therefore,

Around 48.39%children not preferring Superstrength are from England and the probability for child from England did not prefer Superstrength is 0.4839.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Brushing teeth, wasting water? A recent study reported that fewer than half of young adults turn off the water while brushing their teeth. Is the same true for teenagers? To find out, a group of statistics students asked an SRS of 60students at their school if they usually brush with the water off. In the sample, 27students said "Yes." The dotplot shows the results of taking 200SRSS of 60students from a population in which the true proportion who brush with the water off is 0.50.

a. Explain why the sample result (27of the 60students said "Yes") does not give convincing evidence that fewer than half of the school's students brush their teeth with the water off.

b. Suppose instead that 18of the 60students in the class's sample had said "Yes." Explain why this result would give convincing evidence that fewer than 50%of the school's students brush their teeth with the water off.

Four-sided dice A four-sided die is a pyramid whose four faces are labeled

with the numbers 1,2,3and4(see image). Imagine rolling two fair, four-sided dice and

recording the number that is showing at the base of each pyramid. For instance, you would

record a 4if the die landed as shown in the figure.

a. Give a probability model for this chance process.

b. Define event A as getting a sum of 5. Find P(A).

Tossing coins Imagine tossing a fair coin 3times.

a. Give a probability model for this chance process.

b. Define event B as getting more heads than tails. Find P(B).

Lefties A website claims that 10%of U.S. adults are left-handed. A researcher believes that this figure is too low. She decides to test this claim by taking a random sample of 20U.S. adults and recording how many are left-handed. Four of the adults in the sample are left-handed. Does this result give convincing evidence that the website’s 10%claim is too low? To find out, we want to perform a simulation to estimate the probability of getting 4or more left-handed people in a random sample of size 20from a very large population in which 10%of the people are left-handed.

Let 00to 09indicate left-handed and 10to 99 represent right-handed. Move left to Page Number: 311right across a row in Table D. Each pair of digits represents one person. Keep going until you get20 different pairs of digits. Record how many people in the simulated sample are left-handed. Repeat this process many, many times. Find the proportion of trials in which4 or more people in the simulated sample were left-handed.

Superpowers A random sample of 415children from England and the United States who completed a survey in a recent year was selected. Each student’s country of origin was recorded along with which superpower they would most like to have: the ability to fly, ability to freeze time, invisibility, superstrength, or telepathy (ability to read minds). The data are summarized in the two-way table.

Suppose we randomly select one of these students. Define events E: England, T: telepathy,

and S: superstrength.

a. Find P(T|E). Interpret this value in context.

b. Given that the student did not choose superstrength, what’s the probability that this child is from England is ? Write your answer as a probability statement using correct symbols for the events.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free