Question

If a player rolls a $2,3,or12$, it is called craps. What is the probability of getting craps or an even sum on one roll of the dice?

a. $4/36$

b. $18/36$

c. $20/36$

d. $22/36$

e. $32/36$

Short answer

The probability of getting craps or an even sum on one roll of the dice is (d)$22/36$

Step-by-step solution

Given information

We need to find the probability of getting craps or an even sum on one roll of the dice

Explanation

Here , total possibilities will be $36$ ,

Out of it , we have$4$possibilities , of getting craps ( that is getting$2,3,12$on first roll of die )

So probability of getting crap is $4/36$

Also , probablity of getting even sum is $18/36$

As, the events are mutually exclusive ones , we will get ;

the probability of getting craps or an even sum on one roll of the dice $=\frac{18}{36}+\frac{4}{36}=\frac{22}{36}$