Question

Tossing coins Imagine tossing a fair coin $3$times.

a. Give a probability model for this chance process.

b. Define event B as getting more heads than tails. Find P(B).

Short answer

(a) There are total $8$probability outcomes in the probablity model

(b) The probabilty $P\left(B\right)$of getting more heads than tails is$1/2$

Step-by-step solution

Part (a) STEP 1: Given information 

We have been given that a coin is tossed $3$times.

Part (a) STEP 2: Explanation

In a single toss of a coin there are 2 conceivable results specifically Head (H) and Tail (T). So, by the basic rule of duplication, the full number of conceivable results in$3$tosses$=(2\times 2\times 2)=2^3=8.$

Sample space: (HHH,HTH,THH,TTH,HHT,HTT,THT,TTT)

Part (b) STEP 1: Given information

We have been given that a coin is tossed $3$imes.

Part (b) STEP 2: Explanation 

$P\left(B\right)=$Probabilty of getting more heads than tails

$P\left(B\right)=$Total outcomes with $2$or more heads $/$Total outcomes

Total outcomes with two or more heads $=4$

Total outcomes$=8$

$P\left(B\right)=$$4/8=1/2$