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Genetics There are many married couples in which the husband and wife both carry a gene for cystic fibrosis but don’t have the disease themselves. Suppose we select one of these couples at random. According to the laws of genetics, the probability that their first child will develop cystic fibrosis is 0.25.

a. Interpret this probability as a long-run relative frequency.

b. If researchers randomly select 4such couples, is one of these couples guaranteed to have a first child who develops cystic fibrosis? Explain your answer.

Short Answer

Expert verified

a) We find that the firstborn kid will get cystic fibrosis in about 25%of them.

b) The sample size must be quite large in order for the probability to be closely reflected in the sample.

Step by step solution

01

Part (a) Step 1: Given information

We have to interpret this probability as a long-run relative frequency.

02

Part (a) Step 2: Explanation

When we look at numerous couples when both the husband and wife have this gene, we find that the firstborn kid will get cystic fibrosis in about 25%of them.

03

Part (b) Step 1: Given information

We have to explain the answer about first child who develops cystic fibrosis.

04

Part (b) Step 2: Explanation

  • If the family has four children, the sample size is four, which is relatively tiny.
  • The sample size must be quite large in order for the probability to be closely reflected in the sample.

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Most popular questions from this chapter

Is this your card? A standard deck of playing cards (with jokers removed) consists of 52 cards in four suits—clubs, diamonds, hearts, and spades. Each suit has 13 cards, with denominations ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. The jacks, queens, and kings are referred to as “face cards.” Imagine that we shuffle the deck thoroughly and deal one card. The two-way table summarizes the sample space for this chance process based on whether or not the card is a face card and whether or not the card is a heart.

Type of card

Face cardNon-Face cardTotal
Heart3
10
13
Non-Heart9
30
39
Total12
40
52

Are the events “heart” and “face card” independent? Justify your answer.

Languages in Canada Canada has two official languages, English and French. Choose a Canadian at random and ask, “What is your mother tongue?” Here is the distribution of responses, combining many separate languages from the broad Asia/Pacific region

a. Explain why this is a valid probability model.

b. What is the probability that the chosen person’s mother tongue is not English?

c. What is the probability that the chosen person’s mother tongue is one of Canada’s official languages?

Who eats breakfast?Students in an urban school were curious about how many children regularly eat breakfast. They conducted a survey, asking, “Do you eat breakfast on a regular basis?” All 595students in the school responded to the survey. The resulting data are shown in the two-way table.

Suppose we select a student from the school at random. Define event Fas getting a female student and event Bas getting a student who eats breakfast regularly.

a. Find P(BC)

b. Find P(FandBC). Interpret this value in context.

c. Find P(ForBC).

Suppose a loaded die has the following probability model:

If this die is thrown and the top face shows an odd number, what is the probability that the die shows a 1?

a. 0.10

b. 0.17

c. 0.30

d. 0.50

e. 0.60

In an effort to find the source of an outbreak of food poisoning at a conference, a team of medical detectives carried out a study. They examined all 50 people who had food poisoning and a random sample of 200 people attending the conference who didn’t get food poisoning. The detectives found that 40% of the people with food poisoning went to a cocktail party on the second night of the conference, while only 10% of the people in the random sample attended the same party. Which of the following statements is appropriate for describing the 40% of people who went to the party? (Let F = got food poisoning and A = attended party.)

a. P(F|A) = 0.40

b. P(A|FC) = 0.40

c. P(F|AC) = 0.40

d. P(AC|F) = 0.40

e. P(A|F) = 0.40

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