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Exercises T12.4–T12.8 refer to the following setting. An old saying in golf is “You drive for show and you putt for dough.” The point is that good putting is more important than long driving for shooting low scores and hence winning money. To see if this is the case, data from a random sample of 69 of the nearly 1000 players on the PGA Tour’s world money list are examined. The average number of putts per hole (fewer is better) and the player’s total winnings for the previous season are recorded and a least-squares regression line was fitted to the data. Assume the conditions for
inference about the slope are met. Here is computer output from the regression analysis:

T12.8 Which of the following would make the calculation in Exercise T12.7 invalid?

a. If the scatterplot of the sample data wasn’t perfectly linear.

b. If the distribution of earnings has an outlier.

c. If the distribution of earnings wasn’t approximately Normal.

d. If the earnings for golfers with small putting averages was much more variable than the earnings for golfers with large putting averages.

e. If the standard deviation of earnings is much larger than the standard deviation of putting average.

Short Answer

Expert verified

The correct answer is option (d) If the earnings for golfers with small putting averages was much more variable than the earnings for golfers with large putting averages.

Step by step solution

01

Given information

To determine the option that make the calculation in Exercise T12.7invalid.

02

Explanation

For shooting low scores and hence winning money, it is assumed that good putting is more significant than long driving.
A random sample of players is picked for analysis to see if this is the fact.
They assumed that the slope inference conditions were met, and that the data was calculated using the computer output provided in the question.
Assume the researcher is putting the theory to the test.
The test statistic's P-value is 0.0087.
Linear, Normal, Equal standard deviation, and Random are the requirements for regression inference. As a result, after considering our alternatives,
Because the linear requirement requires that the sample data be approximately linear, the calculation will still be correct in option (a).
Because there is no restriction on the distribution of the x-variable or y-variable in option (b), the calculation will still be valid.
Because there is no restriction on the distribution of the x-variable or y-variable in option (c), the calculation will still be valid.
The calculation will no longer be valid in option (d), as the vertical spread in the scatterplot will no longer be constant, violating the equal standard deviations assumption.
Because the equal standard deviation criteria applies to the residuals, option (e) will keep the calculation valid.
As a result, option (d) is the correct answer.

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Most popular questions from this chapter

Could mud wrestling be the cause of a rash contracted by University of Washington students? Two physicians at the university’s student health center wondered about this when one male and six female students complained of rashes after participating in a mud-wrestling event. Questionnaires were sent to a random sample of students who participated in the event. The results, by gender, are summarized in the following table.

Here is some computer output for the preceding table. The output includes the observed counts, the expected counts, and the chi-square statistic.

From the chi-square test performed in this study, we may conclude that

a. there is convincing evidence of an association between the gender of an individual participating in the event and the development of a rash.

b. mud wrestling causes a rash, especially for women.

c. there is absolutely no evidence of any relationship between the gender of an individual participating in the event and the subsequent development of a rash.

d. development of a rash is a real possibility if you participate in mud wrestling, especially if you do so regularly.

e. the gender of the individual participating in the event and the development of a rash are independent.

Section I: Multiple ChoiceChoose the best answer for Questions AP4.1–AP4.40.
AP4.1 A major agricultural company is testing a new variety of wheat to determine whether it is more resistant to certain insects than the current wheat variety. The proportion of a current wheat crop lost to insects is 0.04. Thus, the company wishes to test the following hypotheses:
H0:p=0.04

Ha:p<0.04

Which of the following significance levels and sample sizes would lead to the highest power for this test?
a. n=200 and α=0.01
b. n=400and α=0.05
c.n=400and α=0.01
d. n=500and α=0.01
e. n=500 and α=0.05

How well do professional golfers putt from various distances to the hole? The scatterplot shows various distances to the hole (in feet) and the per cent of putts made at each distance for a sample of golfers.

The graphs show the results of two different transformations of the data. The first graph plots the natural logarithm of per cent made against distance. The second graph plots the natural logarithm of per cent made against the natural logarithm of distance.

a. Based on the scatterplots, would an exponential model or a power model provide a better description of the relationship between distance and per cent made? Justify your answer.

b. Here is computer output from a linear regression analysis of ln(per cent made) and distance. Give the equation of the least-squares regression line. Be sure to define any variables you use.

c. Use your model from part (b) to predict the per cent made for putts of 21 feet.

d. Here is a residual plot for the linear regression in part (b). Do you expect your prediction in part (c) to be too large, too small, or about right? Justify your answer.

Random assignment is part of a well-designed comparative experiment because

a. it is fairer to the subjects.

b. it helps create roughly equivalent groups before treatments are imposed on the subjects.

c. it allows researchers to generalize the results of their experiment to a larger population.

d. it helps eliminate any possibility of bias in the experiment.

e. it prevents the placebo effect from occurring.

If P(A)=0.2and P(B)=0.52 and events A and B are independent, what is P(A or B)?

a. 0.1248

b. 0.28

c. 0.6352

d. 0.76

e. The answer cannot be determined from the given information.

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