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A set of 10cards consists of 5red cards and 5black cards. The cards are shuffled thoroughly, and you choose one at random, observe its color, and replace it in the set. The cards are thoroughly reshuffled, and you again choose a card at random, observe its color, and replace it in the set. This is done a total of four times. Let X be the number of red cards observed in these four trials. The random variable X has which of the following probability distributions?

a. The Normal distribution with mean 2and standard deviation 1

b. The binomial distribution with n=10and p=0.5

c. The binomial distribution with n=5and p=0.5

d. The binomial distribution with n=4and p=0.5

e. The geometric distribution withp=0.5

Short Answer

Expert verified

The correct option is (d) The binomial distribution withn=4andp=0.5

Step by step solution

01

Given information

A set of 10cards consists of 5 red cards and 5 black cards.

02

Explanation 

There are ten cards in total, five red and five black. It is also assumed that the cards are shuffled and that one is chosen at random.

Red has a 0.5probability, while black has a 0.5probability (since5out of the10cards are red and black).

The important part is that the card is replaced and shuffled afresh, ensuring that the next draw is unaffected by the previous one.

This is done four times with the same exact chance of receiving red and black each time.

This would be a binomial experiment ifX is a number of red cards. As a result, option (d) is the proper choice.

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Most popular questions from this chapter

Multiple Choice Select the best answer for Exercises 23-28. Exercises 23-28 refer to the following setting. To see if students with longer feet tend to be taller, a random sample of 25students was selected from a large high school. For each student, x=footlengthand y=heightwere recorded. We checked that the conditions for inference about the slope of the population regression line are met. Here is a portion of the computer output from a least-squares regression analysis using these data:

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cH0:β1=0H0:β1=0versusHα:β10.Hα:β10

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