Question

Munching Froot Loops Kellogg’s Froot Loops cereal comes in six colors:

orange, yellow, purple, red, blue, and green. Charise randomly selected 120 loops and noted the color of each. Here are her data:

Do these data provide convincing evidence at the 5% significance level that Kellogg’s Froot Loops do not contain an equal proportion of each color?

Short answer

There is insufficient evidence to refute Kellogg's assertion that its Froot Loop includes an equal quantity of each flavor.

Step-by-step solution

Given information

Significance level: 5% = 0.05

Concept

Null hypothesis: $H_0$

When the value of $P$ is less than or equal to the significance level, the null hypothesis is rejected.

Explanation

The $P$value is used to calculate the likelihood of a test statistic or a more extreme number.

The P-value in the appendix, which contains the $X^2$value in the row $df=5$may be found in the chi-square distribution table.

$0.15<P<0.20$

When the value of $P$is not less than or equal to the significance level, the null hypothesis is not rejected.

$P>0.05$: fail to reject $H_0$

Hence, There is insufficient evidence to disprove the company's assertion that Kellogg's produces Froot Loop.