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For these data, χ2=69.8with a P-value of approximately 0. Assuming that the researchers used a significance level of 0.05, which of the following is true?

a. A Type I error is possible.

b. A Type II error is possible.

c. Both a Type I and a Type II error are possible.

d. There is no chance of making a Type I or Type II error because the P-value is approximately 0.

e. There is no chance of making a Type I or Type II error because the calculations are correct.

Short Answer

Expert verified

Option a) is correct that is Type I error is possible.

Step by step solution

01

Given Information

We have to identify correct answer for the given data, X2=69.8with a P− value of approximately 0. Assuming the researchers used a significance level of0.05 .

02

Simplification

When X2=69.8with a P value of nearly 0is presented as data, the correct answer is Type I mistake.
Assume that the researchers chose a 0.05significance threshold.

Thus, Option a) is correct.

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Most popular questions from this chapter

Regulating guns The National Gun Policy Survey asked a random sample of adults, "Do you think there should be a law that would ban possession of handguns except for the police and other authorized persons?" Here are the responses, broken down by the respondent's level of education:

Do these data provide convincing evidence at the α=0.05level of an association between education level and opinion about a handgun ban in the adult population?

The manager of a high school cafeteria is planning to offer several new types of food for student lunches in the new school year. She wants to know if each type of food will be equally popular so she can start ordering supplies and making other plans. To find out, she selects a random sample of 100students and asks them, “Which type of food do you prefer: Ramen, tacos, pizza, or hamburgers?” Here are her data:

The chi-square test statistic is

a. (1825)225+(2225)225+(3925)225+(2125)225

b. (2518)218+(2522)222+(2539)239+(2521)221

c. (1825)25+(2225)25+(3925)25+(2125)25

d. (1825)2100+(2225)2100+(3925)2100+(2125)2100

e. (0.180.25)20.25+(0.220.25)20.25+(0.390.25)20.25+(0.210.25)20.25

Sorry, no chi-square How do U.S. residents who travel overseas for leisure differ from

those who travel for business? The following is the breakdown by occupation.

Occupation
Leisure travelers (%)
Business travelers (%)
Professional/technical
36
39
Manager/executive
23
48
Retired
14
3
Student
7
3
Other
20
7
Total
100
100

Explain why we can’t use a chi-square test to learn whether these two distributions differ

significantly.

A Type I error would occur if we found convincing evidence that

a. HCC wiring caused cancer when it actually didn’t.

b. HCC wiring didn’t cause cancer when it actually did.

c. there is no association between the type of wiring and the form of cancer when there actually is an association.

d. there is an association between the type of wiring and the form of cancer when there actually is no association.

e. the type of wiring and the form of cancer have a positive correlation when they actually don’t.

“Will changing the rating scale on a survey affect how people answer the question?” To find out, the group took an SRS of 50students from an alphabetical roster of the school’s just over 1000students. The first 22students chosen were asked to rate the cafeteria food on a scale of 1(terrible) to 5(excellent). The remaining 28students were asked to rate the cafeteria food on a scale of 0(terrible) to 4(excellent). Here are the data:

The students decided to compare the average ratings of the cafeteria food on the two scales.

a. Find the mean and standard deviation of the ratings for the students who were given the 1to5scale.

b. For the students who were given the 0to4scale, the ratings have a mean of 3.21and a standard deviation of 0.568. Since the scales differ by one point, the group decided to add 1to each of these ratings. What are the mean and standard deviation of the adjusted ratings?

c. Would it be appropriate to compare the means from parts (a) and (b) using a two-sample t test? Justify your answer

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