Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Regulating guns The National Gun Policy Survey asked a random sample of adults, "Do you think there should be a law that would ban possession of handguns except for the police and other authorized persons?" Here are the responses, broken down by the respondent's level of education:

Do these data provide convincing evidence at the α=0.05level of an association between education level and opinion about a handgun ban in the adult population?

Short Answer

Expert verified

No, the data is not convincing evidence at the level of an association.

Step by step solution

01

Given information

We need to find out whether the data provided is convincing evidence or not.

02

Explanation

We know that

The null hypothesis asserts that the variables are unrelated, whereas the alternative hypothesis asserts that they are.

H0is there is no association between opinion and education level.

Hαis there is an association between opinion and education level.

And expected frequencies are a product of row and column total divided by table total.

And The squared differences between the actual and predicted frequencies, divided by the expected frequency, make up the chi-square subtotals.

Therefore, the data is not convincing evidence at the level of an association.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Mendel and the peas Gregor Mendel (18221884), an Austrian monk, is considered the father of genetics. Mendel studied the inheritance of various traits in pea plants. One such trait is whether the pea is smooth or wrinkled. Mendel predicted a ratio of 3 smooth peas for every 1 wrinkled pea. In one experiment, he observed 423 smooth and 133 wrinkled peas. Assume that the conditions for inference are met.

a. Carry out a chi-square test for goodness of fit for the genetic model that Mendel predicted.

b. In Chapter 9Exercise 49 you tested Mendel’s prediction using a one-sample z test for a proportion. The hypotheses were H0:p=0.75and Ha:p0.75where p= true proportion of smooth peas. Calculate the z statistic and P-value for this test. How do these values compare to the values from part (a)?

Which test?Determine which chi-square test is appropriate in each of the following settings. Explain your reasoning.

a. Does chocolate help heart-attack victims live longer? Researchers in Sweden randomly selected 1169people who had suffered heart attacks and asked them about their consumption of chocolate in the previous year. Then the researchers followed these people and recorded whether or not they had died within 8years.

b. Random-digit-dialing telephone surveys used to exclude cell-phone numbers. If the opinions of people who have only cell phones differ from those of people who have landline service, the poll results may not represent the entire adult population. The Pew Research Center interviewed separate random samples of cell-only and landline telephone users who were less than 30years old and asked them to describe their political party affiliation

P-values For each of the following, find the P-value using Table C Then

calculate a more precise value using technology.

a. χ2=19.03,df=11

b. χ2=19.03,df=3

Do students who read more books for pleasure tend to earn higher grades in English? The boxplots show data from a simple random sample of 79 students at a large high school. Students were classified as light readers if they read fewer than 3 books for pleasure per year. Otherwise, they were classified as heavy readers. Each student’s average English grade for the previous two

marking periods was converted to a GPA scale, whereA=4.0,A=3.7,B+=3.3

Reading and grades (10.2) Summary statistics for the two groups from Minitab are provided.

a. Explain why it is acceptable to use two-sample t procedures in this setting.

b. Construct and interpret a 95% confidence interval for the difference in the mean English grade for light and heavy readers.

c. Does the interval in part (b) provide convincing evidence that reading more causes a difference in students’ English grades? Justify your answer.

Distance from home A study of first-year college students asked separate random samples of students from private and public universities the following question: “How many miles is this university from your permanent home?” Students had to choose from the following options:5or fewer, 6to 10,11to 50,51to 100,101to 500, or more than 500. Here is the two-way table summarizing the responses:

a. Should we use a chi-square test for homogeneity or a chi-square test for independence in this setting? Justify your answer.

b. State appropriate hypotheses for performing the type of test you chose in part (a). Here is Minitab output from a chi-square test.

c. Check that the conditions for carrying out the test are met.

d. Interpret the P-value. What conclusion would you draw?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free