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We love football! A Gallup poll conducted telephone interviews with a random sample of adults aged 18 and older. Data were obtained for 1000 people. Of these, 370 said that football is their favorite sport to watch on television.

a. Define the parameter p in this setting.

b. What point estimator will you use to estimate p? What is the value of the point estimate?

c. Do you believe that the value of the point estimate is equal to the value of p? Explain your answer.

Short Answer

Expert verified

Part a) The parameter is the population proportion pis the proportion of adults aged 18and older that think their favorite sport to watch on television is football.

Part b) The point estimate of population proportion is 37%

Part c) The point estimate of population proportion can be near top

Step by step solution

01

Part a) Step 1: Given information

n=1000x=370

02

Part a) Step 1: Explanation

First, we must comprehend the concepts of population and parameter.

The population is the set of all possible individuals who share the trait of interest in a study.

A parameter is a numerical characteristic based on observations from a study's entire population of objects.

In this case, the parameter is the population proportion p, which is the proportion of adults aged 18and older who believe football is their favorite sport to watch on television.

03

Part b) Step 1: given information

n=1000x=370

Sample proportionp^=xn

04

Part b) Step 2: Calculation

The sample proportion is the population proportion's point estimate. This is found as,

p^=3701000=0.37=37%

05

Part c) Step 1: Given information

p^=37%

06

Part c) Step 2: Calculation

The sample proportion is the population proportion's point estimate. The sample proportion of 37%is based on sample data, which is a subset of the population. Based on the entire population, different opinions may exist. As a result, we anticipate that the population proportion will be close to 37%

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Most popular questions from this chapter

Batteries A company that produces AA batteries tests the lifetime of a randomsample of 30 batteries using a special device designed to imitate real-world use. Based onthe testing, the company makes the following statement: โ€œOur AA batteries last an average of 430 to 470 minutes, and our confidence in that interval is 95%.โ€36

a. Determine the point estimate, margin of error, standard error, and sample standard

deviation.

b. A reporter translates the statistical announcement into โ€œplain Englishโ€ as follows: โ€œ95% of this companyโ€™s AA batteries last between 430 and 470 minutes.โ€ Comment on this interpretation.

c. Your friend, who has just started studying statistics, claims that there is a 95% probability that the mean lifetime will fall between 430 and 470 minutes. Do you agree? Explain your reasoning.

d. Give a statistically correct interpretation of the confidence level that could be published in a newspaper report.

Itโ€™s critical Find the appropriate critical value for constructing a confidence interval in each of the following settings.

a. Estimating a population proportion p at a 94% confidence level based on an SRS of size 125

b. Estimating a population mean ฮผ at a 99% confidence level based on an SRS of size 58

The Large Counts condition When constructing a confidence interval for a population proportion, we check that both npโˆงandn1-pโˆงare at least 10

a. Why is it necessary to check this condition?

b. What happens to the capture rate if this condition is violated?

Student body totals Use your interval from Exercise 40 to construct and interpret a 99%confidence interval for the total number of students at the school that the student body president can identify by name. Then use your interval to evaluate the presidentโ€™s claim.

Critical values What critical value t*from Table B should be used for a confidence interval for the population mean in each of the following situations?

a. A 90% confidence interval based on n=12 randomly selected observations

b. A 95% confidence interval from an SRS of 30 observations

c. A 99% confidence interval based on a random sample of size 58

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