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You have an SRS of 23observations from a large population. The distribution of sample values is roughly symmetric with no outliers. What critical value would you use to obtain a 98%confidence interval for the mean of the population?

a. 2.177

b. 2.183

c. 2.326

d. 2.500

e. 2.508

Short Answer

Expert verified

Option (e) is correct.

Step by step solution

01

Given Information

Confidence level is98%andn=23

02

Calculation

Level of significance is α=1-0.98=0.02

Degree is freedom is calculated as df=n-1=23-1=22

At 2%level of significance, critical value is tα/2,df=t0.02/2,22

=2.508

Option (e) is correct.

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Most popular questions from this chapter

Critical values What critical value t*from Table B should be used for a

confidence interval for the population mean in each of the following situations?

a. A 95% confidence interval based on n=10 randomly selected observations

b. A99% confidence interval from an SRS of 20 observations

c. A 90% confidence interval based on a random sample of 77 individuals

Most people can roll their tongues, but many can’t. The ability to roll the tongue is

genetically determined. Suppose we are interested in determining what proportion of students can roll their tongues. We test a simple random sample of 400students and find that 317can roll their tongues. The margin of error for a 95%confidence interval for the true proportion of tongue rollers among students is closest to which of the following?

a. 0.0008

b. 0.02

c. 0.03

d. 0.04

e. 0.05

More prayer in school Refer to Exercise 5. Interpret the confidence level.

Losing weight A Gallup poll asked a random sample of U.S. adults, “Would you like to lose weight?” Based on this poll, the 95%confidence interval for the population

proportion who want to lose weight is (0.56,0.62).

a. Interpret the confidence interval.

b. What is the point estimate that was used to create the interval? What is the margin of error?

c. Based on this poll, Gallup claims that more than half of U.S. adults want to lose weight. Use the confidence interval to evaluate this claim.

How confident? The figure shows the result of taking 25SRSs from a Normal population and constructing a confidence interval for the population mean using each sample. Which confidence level—role="math" localid="1654197644211" 80%,90%,95%,or99%—do you think was used? Explain your reasoning.

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