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Rushing for points What is the relationship between rushing yards and points scored in the National Football League? The table gives the number of rushing yards and the number of points scored for each of the 16 games played by the Jacksonville Jaguars in a recent season.

a. Make a scatterplot with rushing yards as the explanatory variable. Describe what you see.

b. The number of rushing yards in Game 16 is an outlier in the x-direction. What effect do you think this game has on the correlation? On the equation of the least-squares regression line? Calculate the correlation and equation of the least-squares regression line with and without this game to confirm your answers.

c. The number of points scored in Game 13 is an outlier in the y-direction. What effect do you think this game has on the correlation? On the equation of the least-squares regression line? Calculate the correlation and equation of the least-squares regression line with and without this game to confirm your answers.

Short Answer

Expert verified

Part (a) The scatterplot confirms a weak relationship because the points seem to lie far apart.

Part (b) The game 16makes the correlation increase.

Part (c) The game 13 makes the correlation decrease.

Step by step solution

01

Part (a) Step 1: Given information

02

Part (a) Step 2: Explanation

The scatterplot with rushing yards as the explanatory variable is as:

Because the scatterplot slopes upwards, we can conclude that the scatterplot confirms a positive linear connection. Because the points appear to be widely apart, the scatterplot indicates a weak association.

03

Part (b) Step 1: Explanation

For the case with outlier:

Using a calculator, press on STAT and then select 1 : Edit. and then enter the data of sugar in the list L1 and enter the data of calories in the list L2

Next, press on STAT select CALC, and then select Linreg(a + bx) . Next, we need to finish the command by entering L1L2

Linreg(a + bx)L1L2

Finally, pressing on ENTER then gives us the following result:

y = a + bx

a = 11.3891

b = 0.0308

r = 0.1

This then implies the regression line as:

Y= a + bx

⇒Y = 11.3891 + 0.0308x

For the case without outlier:

Using a calculator, press on STAT and then select 1 : Edit. and then enter the data of sugar in the list L1 and enter the data of calories in the list L2

Next, press on STAT select CALC, and then select Linreg(a + bx) . Next, we need to finish the command by entering L1L2

Linreg(a + bx)L1L2

Finally, pressing on ENTER then gives us the following result:

y = a + bx

a = 14.0336

b = 0.0076

r = 0.0180

This then implies the regression line as:

Y= a + bx

⇒Y = 14.0336 + 0.0076x

Thus, we note that the correlation coefficient with the outlier is more than the correlation coefficient without the outlier. We then note that the outlier increases the correlation due to the fact that game 16 as the correlation is much higher. When the outlier is removed the regression line becomes much more horizontal and thus game 16 makes the regression line less horizontal.

04

Part (c) Step 1: Explanation

For the case with outlier:

Using calculator, press on STAT and then select 1 : Edit . and then enter the data of sugar in the list L1 and enter the data of calories in the list L2

Next, press on STAT select CALC and then select Linreg(a + bx) . Next we need to finish thecommand by entering L1L2

Linreg(a + bx)L1L2

Finally, pressing on ENTER then gives us the following result:

y = a + bx

a = 11.3891

b = 0.0308

r = 0.1

This then implies the regression line as:

Y= a + bx

⇒ Y= 11.3891 + 0.0308x

For the case without outlier:

Using calculator, press on STAT and then select 1: Edit . and then enter the data of sugar in the list L1 and enter the data of calories in the list L2

Next, press on STAT select CALC and then select Linreg(a + bx) . Next we need to finish thecommand by entering L1L2

Linreg(a + bx)L1L2

Finally, pressing on ENTER then gives us the following result:

y = a + bx

a = 7.2776

b = 0.0505

r = 0.3182

This then implies the regression line as:

Y= a + bx

⇒Y = 7.2776 + 0.0505x

Thus, we note that the correlation coeff icient with the outlier is more than the correlationcoeff icient without outlier. Then the game 13 makes the correlation decrease as the correlationcoeff icient is much lower. When the outlier is removed the regression line becomes much steeperand thus the game 13 makes the regression line steep.

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Most popular questions from this chapter

If we leave out the low outlier, the correlation for the remaining 13 points in the preceding figure is closest to

a. −0.95.

b. −0.65.

c. 0.

d. 0.65.

e. 0.95.

Born to be old? Is there a relationship between the gestational period (time from conception to birth) of an animal and its average life span? The figure shows a scatterplot of the gestational period and average life span for 43 species of animals.

a. Describe the relationship shown in the scatterplot.

b. Point A is the hippopotamus. What effect does this point have on the correlation, the equation of the least-squares regression line, and the standard deviation of the residuals?

c. Point B is the Asian elephant. What effect does this point have on the correlation, the equation of the least-squares regression line, and the standard deviation of the residuals?

A carpenter sells handmade wooden benches at a craft fair every week. Over the past year, the carpenter has varied the price of the benches from \(80

to \)120 and recorded the average weekly profit he made at each selling price. The prices of the bench and the corresponding average profits are shown in the table.

a. Make a scatterplot to show the relationship between price and profit.

b. The correlation for these data is r=0Explain how this can be true even though there is a strong relationship between price and average profit.

Suppose that a tall child with an arm span of 120 cm and a height of 118 cm was added to the sample used in this study. What effect will this addition have on the correlation and the slope of the least-squares regression line?

a. Correlation will increase, and the slope will increase.

b. Correlation will increase, and the slope will stay the same.

c. Correlation will increase, and the slope will decrease.

d. Correlation will stay the same, and the slope will stay the same.

e. Correlation will stay the same, and the slope will increase.

When we standardize the values of a variable, the distribution of standardized values has a mean of 0 and a standard deviation of 1. Suppose we measure two variables X and Y on each of several subjects. We standardize both variables and then compute the least squares regression line. Suppose the slope of the least-squares regression line is 20.44. We may conclude that

a. the intercept will also be −0.44.

b. the intercept will be 1.0.

c. the correlation will be 1/−0.44.

d. the correlation will be 1.0.

e. the correlation will also be −0.44.

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