Question

Here are the weights (in milligrams) of $58$ diamonds from a nodule

carried up to the earth’s surface in surrounding rock. These data represent a population of diamonds formed in a single event deep in the earth.

Make a histogram to display the distribution of weight. Describe the distribution.

Short answer

The distribution is skewed to right, spread from $0$ to $35$ with center at $2.5$ and without outliers.

Step-by-step solution

Given information

Data illustrating the population of diamonds generated in a single deep-earth event:

Calculation

Frequency table:

Calculate the frequency of each interval, which is the number of data values that fall within it.

The first value of the first interval is $0$ having a width of $5$

Thus,

The first interval is $0-<5$

The interval follows

$5-<10,10-<15$ etc.

The intervals will be established until all of the data values are assigned to exactly one interval.

Frequency Histogram:

Interval bounds must be used to define the bars, and each bar's width must be the same.

Whereas, the height needs to be equal to the frequency.

Spread: In the data set, the weight appears to range from $0.1$ to $33.8$ and in the histogram, it appears to range from $0$ to $35$

Shape: The highest bars are on the left of the histogram, with a tail of smaller balls to the right. As a result, the shape will be slanted toward the right.

Outliers: There are no outliers because the histogram has no gaps.

Because it is in the middle of the highest bar, the distribution's center looks to be around $2.5$