Question

A smash or a hitRefer to Exercise 23.

(a) What proportion of subjects who said they saw broken glass at the accident received the “hit” treatment?

(b) What percent of subjects who received the “smashed into” treatment said they did not see broken glass at the accident?

Short answer

Part (a) 0.2414

Part (b) 68%

Step-by-step solution

Part (a) Step 1. Given information.

The given table in Excercise 23 is shown below:

Part (a) Step 2. Determine the proportion of subjects who reported broken glass. were given "hit " treatment.

We noted from the given table that 29 $\left(16+7+6\right)$of the 150 respondents indicated "Yes," implying that 29 people saw broken glass at the accident.

Furthermore, we note that 7 of the 29 participants who reported seeing broken glass at the accident were given the "hit" treatment (as 7 is indicated in the row "Yes" and the column "Hit").

Then the required proportion is:

$\frac{7}{29}\approx 0.2414$

Part (b) Step 1. Determine the percent of subjects who do not report broken glass and were given "smashed into treatment.

The study included 150 participants, with 50 being assigned to each treatment, and so 50 is assigned to the "Smashed into".

We also observe that 34 of the 50 patients who received the "Smashed into" treatment reported they did not see broken glass at the accident (as 34 are indicated in the table's row "Not" and column "Smashed into").

Then the required percent is:

$\frac{34}{50}=\frac{17}{25}\mathrm{or}68\%$