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Each day I am getting better in math A "subliminal" message is below our threshold of awareness but may nonetheless influence us. Can subliminal messages help students learn math? A group of 18students who had failed the mathematics part of the City University of New York Skills Assessment Test agreed to participate in a study to find out. All received a daily subliminal message, flashed on a screen too rapidly to be consciously read. The treatment group of 10students (assigned at random) was exposed to "Each day I am getting better in math." The control group of 8students was exposed to a neutral message, "People are walking on the street." All 18students participated in a summer program designed to improve their math skills, and all took the assessment test again at the end of the program. The following table gives data on the subjects' scores before and after the program.

a. Explain why a two-sample t-test and not a paired t-test is the appropriate inference procedure in this setting.

b. The following boxplots display the differences in pretest and post-test scores for the students in the control (C) and treatment (T) groups. Write a few sentences comparing the performance of these two groups.

c. Do the data provide convincing evidence at the α=0.01,3051526=0.200=20%significance level that subliminal messages help students like the ones in this study learn math, on average?

d. Can we generalize these results to the population of all students who failed the mathematics part of the City University of New York Skills Assessment Test? Why or why not?

Short Answer

Expert verified

(a) As students are assigned to one of the samples randomly.

(b) The Control distribution is heavily skewed to the right, whereas the Treatment distribution is marginally tilted to the left. The Treatment group's center is higher than the Control group's center. The spread between the two distributions appears to be similar. The distributions do not appear to have any outliers.

(c) No, There is no convincing evidence for subliminal messages that help students like the ones in this study learn math, on average.

(d) No, we can not generalize the result of all the students failed in mathematics.

Step by step solution

01

Part (a) Step 1: Given information

We need to find the reason for the two-sample t-test.

02

Part (a) Step 2: Explanation 

The first sample contains the treatment group's ten pupils, whereas the second sample comprises the control group's eight students.

Because the students were assigned to one of the samples at random, the students in the two samples will be completely unrelated, making the two-sample t-methods suitable.

03

Part (b) Step 1: Given information

We need to interpret the given boxplot.

04

Part (b) Step 2: Explanation

We know that

  • Because the box of the boxplot is to the left between the whiskers, the Control distribution is heavily skewed to the right. Because the box of the boxplot leans somewhat to the right between the whiskers, the Treatment distribution is slightly skewed to the left.
  • Because the box of the Treatment boxplot lies further to the right than the box of the Control boxplot, the center of the Treatment group is higher than the center of the Control group.
  • Because the two boxplots are almost the same width, the spread of the two distributions seems to be about the same.
  • Unusual features: There appear to be no outliers in the distributions, as neither boxplot has independent dots.
05

Part (c) Step 1: Given information

We need to find whether there is convincing for evidence subliminal messages help students like the ones in this study learn math, on average.

06

Part (c) Step 2: Explanation

We know that

We know that

The null hypothesis asserts that the variables are unrelated, whereas the alternative hypothesis asserts that they are.

H0:μ1=μ2Hα:μ1<μ2

where μ1=true mean difference for students does not receive the treatment.

And μ2=true mean difference for students receiving the treatment.

And expected frequencies are a product of row and column total divided by table total.

And The squared differences between the actual and predicted frequencies, divided by the expected frequency, make up the chi-square subtotals.

Therefore, the data is no convincing evidence for subliminal messages that help students like the ones in this study learn math, on average.

07

Part (d) Step 1: Given information

We need to find whether the result can be generalized or not.

08

Part (d) Step 2: Explanation

We know that

  • The kids opted to participate, the sample is not random, and it is possible that some students declined to participate.
  • The students who accepted to participate may have different features than those who refused, causing us to continually overestimate or underestimate the mean difference.

This means that we can't extrapolate the findings to the entire population of students who failed the mathematics section of the City University of New York Skills Assessment Tests, because we can't be sure whether the differences are due to the treatment or to the students' different characteristics (compared to the general population).

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Most popular questions from this chapter

Suppose the probability that a softball player gets a hit in any single at-bat is 0.300. Assuming that her chance of getting a hit on a particular time at bat is independent of her other times at bat, what is the probability that she will not get a hit until her fourth time at bat in a game?

a.(43)(0.3)1(0.7)33051526=0.200=20.0%43(0.3)1(0.7)3

b.(43)(0.3)3(0.7)13051526=0.200=20.0%43(0.3)3(0.7)1

C.(41)(0.3)3(0.7)13051526=0.200=20.0%41(0.3)3(0.7)1

d.(0.3)3(0.7)13051526=0.200=20.0%(0.3)3(0.7)1

e.(0.3)1(0.7)33051526=0.200=20.0%(0.3)1(0.7)3

Let X represent the outcome when a fair six-sided die is rolled. For this random variable, μX=3.5and σX=1.71. If the die is rolled 100 times, what is the approximate probability that the sum is at least 375?

a. 0.0000

b.0.0017

c.0.0721

d.0.4420

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Literacy A researcher reports that 80%of high school graduates, but only 40%of high school dropouts, would pass a basic literacy test. Assume that the researcher’s claim is true. Suppose we give a basic literacy test to a random sample of 60high school graduates and a separate random sample of 75high school dropouts.p^G,p^Dbe the sample proportions of graduates and dropouts, respectively, who pass the test.

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Researchers want to evaluate the effect of a natural product on reducing blood pressure. They plan to carry out a randomized experiment to compare the mean reduction in blood pressure of a treatment (natural product) group and a placebo group. Then they will use the data to perform a test of H0:μTμP=0versus Ha:μTμP>0, where μT= the true mean reduction in blood pressure when taking the natural product and μP = the true mean reduction in blood pressure when taking a placebo for subjects like the ones in the experiment. The researchers would like to detect whether the natural product reduces blood pressure by at least 7points more, on average, than the placebo. If groups of size 50are used in the experiment, a twosample t test using α=0.01will have a power of 80%to detect a 7-point difference in mean blood pressure reduction. If the researchers want to be able to detect a 5-point difference instead, then the power of the test

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b. would be greater than 80%.

c. would still be 80%.

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A survey asked a random sample of U.S. adults about their political party affiliation and how long they thought they would survive compared to most people in their community if an apocalyptic disaster were to strike. The responses are summarized in the following two-way table.

Suppose we select one of the survey respondents at random. Which of the following probabilities is the largest?

a. P(Independent and Longer)

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c. P(Democrat 3051526=0.200=20.0%| Not as long)

d. P(About as long 3051526=0.200=20.0%| Democrat)

e. P(About as long)

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