Question

There are two common methods for measuring the concentration of a pollutant in fish tissue. Do the two methods differ, on average? You apply both methods to each fish in a random sample of $18$carp and use

a. the paired t test for $\mu diff\frac{305}{1526}=0.200=20.0\%\mu diff$.

b. the one-sample z test for p.

c. the two-sample t test for $\mu 1-\mu 2\frac{305}{1526}=0.200=20.0\%\mu 1-\mu 2$.

d. the two-sample z test for $p1-p2\frac{305}{1526}=0.200=20.0\%p1-p2$.

e. none of these.

Short answer

The correct option is:

a. the paired t test for $\mu diff\frac{305}{1526}=0.200=20.0\%\mu diff$

Step-by-step solution

Step 1 -  Given information:

We have been given that:

Fish in a random sample of $18$crap.

Step 2 -  Explanation:

Generally:

One percentage z-test/interval: one sample

Two proportions z-test/interval: two samples

a case study one mean, t-test/interval

There are two possibilities: on two samples t-test/interval

Using two samples of data, two means or mean difference: t-test/interval paired t-test

If you're looking for a difference, quality, rise, or decline, a test is a good way to go.

Use an interval to approximate the real value's range.

Because both procedures are used on the same sample, the paired t-test is used.