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I want red! Refer to Exercise 1.

a. Find the probability that the proportion of red jelly beans in the Child sample is less than or equal to the proportion of red jelly beans in the Adult sample, assuming that the company’s claim is true.

b. Suppose that the Child and Adult samples contain an equal proportion of red jelly beans. Based on your result in part (a), would this give you reason to doubt the

company’s claim? Explain your reasoning.

Short Answer

Expert verified

a. P(z<-2.03)=0.2118

b. There is reason to doubt company's claim.

Step by step solution

01

Given Information

It is given that μ=0.15

σ=0.07399

02

Calculating the Probability

We know that z=x-μσ

=0-0.150.07399=-2.03

From standard normal distribution table, P(z<-2.03)=0.2118

=2.118%

03

Reason for Company's Claim

As P(z<-2.03)=2.118%, which is very small.

It gives reason to doubt company's claim.

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Most popular questions from this chapter

Two samples or paired data? In each of the following settings, decide whether you should use two-sample t procedures to perform inference about a difference in means or paired t procedures to perform inference about a mean difference. Explain your choice.

a. To test the wear characteristics of two tire brands, A and B, each of 50cars of the same make and model is randomly assigned Brand A tires or Brand B tires.

b. To test the effect of background music on productivity, factory workers are observed. For one month, each subject works without music. For another month, the subject works while listening to music on an MP3 player. The month in which each subject listens to music is determined by a coin toss.

c. How do young adults look back on adolescent romance? Investigators interviewed a random sample of 40couples in their mid-twenties. The female and male partners were interviewed separately. Each was asked about his or her current relationship and also about a romantic relationship that lasted at least 2months when they were aged 15or 16. One response variable was a measure on a numerical scale of how much the attractiveness of the adolescent partner mattered. You want to find out how much men and women differ on this measure.

Shortly before the 2012presidential election, a survey was taken by the school newspaper at a very large state university. Randomly selected students were asked, “Whom do you plan to vote for in the upcoming presidential election?” Here is a two-way table of the responses by political persuasion for 1850students:

Candidate of

choice


Political persuasion

Democrat
Republican
Independent
Total
Obama
925
78
26
1029
Romney
78
598
19
695
Other
2
8
11
21
Undecided
32
28
45
105
Total
1037
712
101
1850

Which of the following statements about these data is true?

a. The percent of Republicans among the respondents is 41%.

b. The marginal relative frequencies for the variable choice of candidate are given by

Obama: 55.6%; Romney: 37.6%; Other: 1.1%; Undecided: 5.7%.

c. About 11.2%of Democrats reported that they planned to vote for Romney.

d. About 44.6%of those who are undecided are Independents.

e. The distribution of political persuasion among those for whom Romney is the

candidate of choice is Democrat: 7.5%; Republican: 84.0%; Independent: 18.8%.

Children make choices Refer to Exercise 15.

a. Explain why the sample results give some evidence for the alternative hypothesis.

b. Calculate the standardized test statistic and P-value.

c. What conclusion would you make?

Friday the 13thRefer to Exercise 88.

a. Construct and interpret a 90%confidence interval for the true mean difference. If you already defined parameters and checked conditions in Exercise 88, you don’t need to do them again here.

b. Explain how the confidence interval provides more information than the test in Exercise 88.

A beef rancher randomly sampled 42 cattle from her large herd to obtain a 95%confidence interval for the mean weight (in pounds) of the cattle in the herd. The interval obtained was (1010,1321). If the rancher had used a 98%confidence interval instead, the interval would have been

a. wider with less precision than the original estimate.

b. wider with more precision than the original estimate.

c. wider with the same precision as the original estimate.

d. narrower with less precision than the original estimate.

e. narrower with more precision than the original estimate.

See all solutions

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