Question

For the job satisfaction study described in Section 9.1, the hypotheses are

$$\begin{gathered} H_0:\mu =0 \\ {H}_a:\mu \ne 0 \end{gathered}$$

where $\mu$is the mean difference in job satisfaction scores (self-paced -machine-paced) in the population of assembly-line workers at the company. Data from a random sample of $18$workers gave $\overline{x}=17$and $s_x=60$

Now use your calculator to find the P-value as described in the Technology Corner. Is your result consistent with the value you obtained in Question $2$?

Short answer

The $P-$value is $0.221$

Step-by-step solution

Given information

Degree of freedom $(df)=17$

Test statistic $\left(t\right)=1.27$

Concept

test statistic = $\frac{statisticparameter}{s\tan darddeviationofstatistic}$

Calculation

The $P-$value technology can be computed as:

The above value is for one-tailed.

The P-value for two-tailed can be calculated as: $$\begin{gathered} P-value=2\times 0.1105 \\ =0.221 \end{gathered}$$

Here, also the $P-$value is $0.221$

Thus, it could be said that the obtained $P-$value is matching to the value that has been computed in the previous problem.