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Refer to Exercise 5.

(a) Interpret the value of SEb in context.

(b) Find the critical value for a 90% confidence interval for the slope of the true regression line. Then calculate the confidence interval. Show your work.

(c) Interpret the interval from part (b) in context.

(d) Explain the meaning of “90% confident” in context.

Short Answer

Expert verified

(a) SEb=0.002456

(b) The confidence interval is (0.004244,0.012894)

(c) As a result, we have 90 percent confldence that the true slope of the population regression line is between (0.004244,0.012894)

(d) "confident" means that the confidence interval will contain the correct value of the population parameter in 90 of all available samples.

Step by step solution

01

Part (a)Step 1: Given information

Given in the question that, We need to Interpret the value of SEbin context .

02

Part(a) Step 2: Explanation

In order to answer the topic, researchers looked at how nature manages the size of animal predators that destroy a bigger proportion of the population when prey density is low. The amount of perch in a confined region is the explanatory variable, and the proportion of perch killed by bass in two hours while bass have access to the perch is the response variable. A scatterplot is provided, which depicts a linear relationship. Also included is a residual graphic for the least square regression line. For this data, the computer output is provided. The standard deviation of the slope is supplied in the row with "Perch" and the column with "Stdev.":SEb

SEb=0.002456

This indicates that the slope is steep.

03

Part(b) Step 1: Given information

We need to interpret the interval from part (b) in context.

04

Part (b) Step 2: Explanation

In order to answer the topic, researchers looked at how nature manages the size of animal predators that destroy a bigger proportion of the population when prey density is low. The amount of perch in a confined region is the explanatory variable, and the proportion of perch killed by bass in two hours while bass have access to the perch is the response variable. A scatterplot is provided, which depicts a linear relationship. Also included is a residual graphic for the least square regression line. For this data, the computer output is provided. As a result, it is stated,

n=16

b=0.008569

SEb=0.002456

The sample size was reduced by two degrees of freedom:

df=n-2

=16-2

=14

In tablet, the critical B-value can be located in the row of df=14and the column of c=90%as

t*=1.761

As a result, the confidence interval is as follows:

b-t*×SEb

=0.008569-1.761×0.002456

=0.004244

b+t*×SEb

=0.008569+1.761×0.002456

=0.012894

05

Part(c) Step 1: Given information

Given in the question that, We need to interpret the interval from part (b) in context.

06

Part(c) Step 2: Explanation

In order to answer the topic, researchers looked at how nature manages the size of animal predators that destroy a bigger proportion of the population when prey density is low. The amount of perch in a confined region is the explanatory variable, and the proportion of perch killed by bass in two hours while bass have access to the perch is the response variable. A scatterplot is provided, which depicts a linear relationship. Also included is a residual graphic for the least square regression line. For this data, the computer output is provided. As a result of portion (b),(0.004244,0.012894)

As a result, we have 90percent confidence that the true slope of the population regression line is between (0.004244,0.012894).

07

Part(d) Step 1: Given information

Given in the question that, We need to explain the meaning of “90% confident” in context.

08

Part(d) Step 2: Explanation

In order to answer the topic, researchers looked at how nature manages the size of animal predators that destroy a bigger proportion of the population when prey density is low. The amount of perch in a confined region is the explanatory variable, and the proportion of perch killed by bass in two hours while bass have access to the perch is the response variable. A scatterplot is provided, which depicts a linear relationship. Also included is a residual graphic for the least square regression line. For this data, the computer output is provided. In this instance, "confident" means that the confidence interval will contain the correct value of the population parameter in 90% of all available samples.

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Most popular questions from this chapter

Park rangers are interested in estimating the weight of the bears that inhabit their state. The rangers have data

on weight (in pounds) and neck girth (distance around the neck in inches) for 10 randomly selected bears. Some

regression output for these data is shown below.

Which of the following represents a 95% confidence interval for the true slope of the least-squares regression line relating the weight of a bear and its neck girth?

(a)241.710±38.57(b)241.70±88.94(c)20.230±1.695(d)20.230±3.83(e)20.230±3.91

A distribution that represents the number of cars parked in a randomly selected residential driveway on any night is given by

xi:0 123 4
pi :0.10.20.350.250.15

Which of the following statements is correct?

(a) This is a legitimate probability distribution because each of the pi-values is between 0and 1.

(b) This is a legitimate probability distribution because xiis exactly 10.

(c) This is a legitimate probability distribution because each of the pi-values is between 0and 1and the xiis exactly 10.

(d) This is not a legitimate probability distribution because xiis not exactly 10.

(e) This is not a legitimate probability distribution because role="math" localid="1650523963322" pi is not exactly 1.

A 95% confidence interval for the slope B of the population regression line is

The P-value for the test in Question 5 is 0.0087. A correct interpretation of this result is that

(a) the probability that there is no linear relationship between an average number of putts per hole and total winnings for these 69players is 0.0087.

(b) the probability that there is no linear relationship between the average number of putts per hole and total winnings for all players on the PGA Tour’s world money list is 0.0087.

(c) if there is no linear relationship between an average number of putts per hole and total winnings for the players in the sample, the probability of getting a random sample of 69players yields a least-squares regression line with a slope of -4139198or less is 0.0087.

(d) if there is no linear relationship between an average number of putts per hole and total winnings for the players on the PGA Tour’s world money list, the probability of getting a random sample of 69 players yields a least-squares regression line with a slope of -4139198or less is 0.0087.

(e) the probability of making a Type II error is0.0087.

Prey attracts predators Refer to Exercise 3. Computer output from the least-squares regression analysis on the perch data is shown below.

The model for regression inference has three parameters: α,βand σ. Explain what each parameter represents in context. Then provide an estimate for each.

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