Question

A company has been running television commercials for a new children’s product on five different

family programs during the evening hours in a large city over a one-month period. A random sample of families is taken, and they are asked to indicate the one program they viewed most often and their rating of the advertised product. The results are summarized in the following table.

The advertiser decided to use a chi-square test to see if there is a relationship between the family program viewed and the product’s rating. What would be the degrees of freedom for this test?

(a) 3 (c) 12 (e) 19

(b) 4 (d) 18

Short answer

The degree of freedom for this test is$12$

Step-by-step solution

Given information

We have been given that A company has been running television commercials for a new children’s product on five different family programs during the evening hours in a large city over a one-month period.

The number of columns of the given table is $c=5$

The number of row of the given table is $r=4$

And this formula is used in this question$df=(c-1)(r-1)$

Explanation

The degree of freedom is the product of the number of columns decreased by 1 and the number of rows decreased by 1:

$df=(c-1)(r-1)=(5-1)(4-1)=\left(4\right)\left(3\right)=12$