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Stats teachers' cars A random sample of AP Statistics teachers were asked to report the age (in years) and mileage of their primary vehicles. A scatterplot of the data is shown below.

Computer output from a least-squares regression analysis of these data is shown below. Assume that the conditions for regression inference are met.

(a) Verify that the 95% confidence interval for the slope of the population regression line is (9016.4, 14,244.8 ).

(b) A national automotive group claims that the typical driver puts 15,000 miles per year on his or her main vehicle. We want to test whether AP Statistics teachers are typical drivers. Explain why an appropriate pair of hypotheses for this test is H0:β=15,000versus Ha:β15,000.

(c) What conclusion would you draw for this significance test based on your interval in part (a)? Justify your answer.

Short Answer

Expert verified

a) (9016.443,14244.757)

b) H0:β=15000

Ha:β15000

c)There is sufficient evidence to reject the claim that AP Statistics teachers are typical drivers.

Step by step solution

01

Given Information(Part a)

Given:

n=21b=11630.6SEb=1249

02

Explanation(Part a)

The degrees of freedom is the sample size decreased by 2 :

df=n-2=21-2=19

The critical t-value can be found in table B in the row of d f=19 and in the column of c=95% :

t*=2.093

The boundaries of the confidence interval then become:

localid="1650543247381" b-t*×SEb=11630.6-2.093×1249=9016.443

localid="1650543258240" b+t*×SEb=11630.6+2.093×1249=14244.757

The slight deviation is due to rounding errors.

03

Given Information(Part b)

Need for an appropriate pair of hypotheses for this test.

04

Explanation (Part b)

Claim: the typical driver puts 15000 miles per year on his or her main vehicle.

This means that the mileage is expected to be about 15000 miles per year, which corresponds with a slope of 15000. The null hypothesis states that the population parameter is equal to the value given in the claim:

H0:β=15000

The alternative hypothesis states the opposite of the null hypothesis:

Ha:β15000

05

Given Information(Part c)

Need to find this significance test based on your interval in part (a).

06

Explanation(Part c)

H0:β=15000

Ha:β15000

Confidence interval found in part a:

(9016.443,14244.757)

The confidence interval does not contain 15000 and thus it is unlikely to obtain β=15000, which means that there is sufficient evidence to reject the claim that AP Statistics teachers are typical drivers.

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Most popular questions from this chapter

A set of10 cards consists of 5 red cards and5 black cards. The cards are shuffled thoroughly, and you choose one at random, observe its color, and replace it in the set. The cards are thoroughly reshuffled, and you again choose a card at random, observe its color, and replace it in the set. This is done a total of four times. Let X be the number of red cards observed in these four trials.

The random variableX has which of the following probability distributions?

(a) The Normal distribution with mean2 and standard deviation1

(b) The binomial distribution with n=10androle="math" localid="1650534915843" p=0.5

(c) The binomial distribution withn=5 and p=0.5

(d) The binomial distribution with n=4and p=0.5

(e) The geometric distribution with p=0.5

Snowmobiles

(a) If we choose a survey respondent at random, what’s the probability that this individual (i) is a snowmobile owner? (ii) belongs to an environmental organization or owns a snowmobile? (iii) has never used a snowmobile given that the person belongs to an environmental organization?

(b) Are the events “is a snowmobile owner” and “belongs to an environmental organization” independent for the members of the sample? Justify your answer.

(c) If we choose two survey respondents at random, what’s the probability that (i) both are snowmobile owners? (ii) at least one of the two belongs to an environmental organization?

An old saying in golf is “You drive for show and you putt for dough.” The point is that good putting is more important than long driving for shooting low scores and hence winning money. To see if this is the case, data from a random sample of 69of the nearly 1000players on the PGA Tour’s world money list are examined. The average number of putts per hole and the player’s total winnings for the previous season is recorded. A least-squares regression line was fitted to the data. The following results were obtained from statistical software.

Suppose that the researchers test the hypotheses H0:β=0: Ha:β<0. The value of the t statistic for this test is

(a)2.61

(b)2.44

(c)0.081

(d)-2.44

(e) -20.24

The P-value for the test in Question 5 is 0.0087. A correct interpretation of this result is that

(a) the probability that there is no linear relationship between an average number of putts per hole and total winnings for these 69players is 0.0087.

(b) the probability that there is no linear relationship between the average number of putts per hole and total winnings for all players on the PGA Tour’s world money list is 0.0087.

(c) if there is no linear relationship between an average number of putts per hole and total winnings for the players in the sample, the probability of getting a random sample of 69players yields a least-squares regression line with a slope of -4139198or less is 0.0087.

(d) if there is no linear relationship between an average number of putts per hole and total winnings for the players on the PGA Tour’s world money list, the probability of getting a random sample of 69 players yields a least-squares regression line with a slope of -4139198or less is 0.0087.

(e) the probability of making a Type II error is0.0087.

The slope β of the population regression line describes

(a) the exact increase in the selling price of an individual unit when its appraised value increases by \(1000

(b) the average increase in the appraised value in a population of units when the selling price increases by \)51000.

(c) the average increase in selling price in a population of units when the appraised value increases by \( 1000.

(d) the average selling price in a population of units when a unit's appraised value is 0.

(e) the average increase in appraised value in a sample of 16 units when the selling price increases by \) 1000.

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