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Use Table A to find the value zfrom the standard Normal distribution that satisfies each of the following conditions. In each case, sketch a standard Normal curve with your value of zmarked on the axis. Use your calculator or the Normal Curve applet to check your answers.

Working backward

(a) The 63rd percentile.

(b) 75% of all observations are greater than z.

Short Answer

Expert verified

From the given information

a) The value of zcorresponding to 63rd percentile is 0.33

b) The value of zsuch that 75% of observations are above z is -0.67

Step by step solution

01

Part (a) Step 1: Given Information

The63rd percentile.

02

Part (a) Step 2: Explanation

It's assumed that we find the value of zthat meets the following conditions.

a) We are expected to find a value that equals 0.63.

The 63percentile refers to the fact that 63%of occurrences fall below this value.

We can find zto be 0.63by using the following standard normal table.

03

Part (a) Step 3: Explanation

The above table shows that the zvalue for 0.63is 0.33.

The following graph shows what the 63rdpercentile looks like along with the correspondingzvalue:

So, the value ofzcorresponding to localid="1649782327484" 63rd percentile is 0.33

04

Part (b) Step 1: Given Information

It is given in the question that, 75% of all observations are greater than z.

05

Part (b) Step 2: Explanation

As a result of finding the value of zwith a 75%probability that 75%of observed data is above z, we assume that 25%of observations are below z.

06

Part (b) Step 3: Explanation

Observing the table above, we can deduce that the value corresponds to the approximate value of0.25is -0.67.

Hence, the value of zsuch that 75% observations are above z is -0.67

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