Question

Table A practice

(a) $z<-2.46$.

(b) $z>2.46$

(c) $0.89<z<2.46$

(d) $-2.95<z<-1.27$

Short answer

a).$Area(z<-2.46)=0.0069$.

b). Area $(z>2.46)=0.0069$.

c). The area between $z=0.89{}^{\star \star }z=2.46$is $0.9931-0.8133=0.1798$.

d). The area between $z=-2.95\&z=-1.27$is $0.1020-0.0016=[0.1004]$

Step-by-step solution

Part (a) Step 1: Given Information

Find the fraction of standard normal distribution observations that satisfy each of the following statements using Table A. Draw a standard normal curve in each scenario and shade the area under the curve that corresponds to the answer to the question.

Part (a) Step 2: Explanation

The table of areas beneath the standard normal curve is called the below standard normal probabilities table. The area under the curve to the left of each number $z$is the table entry.

Part (a) Step 3: Explanation

The area to the left of $z=-2.46$is $0.0069$.

Part (b) Step 1: Given Information

Find the fraction of standard normal distribution observations that satisfy each of the following statements using Table A. Draw a standard normal curve in each scenario and shade the area under the curve that corresponds to the answer to the question.

Part (b) Step 2: Explanation

The area to the left of $z=2.46$is $0.991$. Thus, the area to the right of $z=2.46$is $1-0.9931=0.0069$.

Part (c) Step 3: Given Information

Find the fraction of standard normal distribution observations that satisfy each of the following statements using Table A. Draw a standard normal curve in each scenario and shade the area under the curve that corresponds to the answer to the question.

Part (c) Step 2: Explanation

From the Standard Normal probabilities table, the area to the left of $-=0,89$is $0.8133$and the area to the left of $z=2.46$is $0.9931$. The area between $z=2.46$and $z=0.89$is the area to the left of $2.46$minus the area to the left of $0.89$.

Therefore, the area between $z=0.89\&z=2.46$is $0.9931-0.8133=0.1798$.

Part (d) Step 1: Given Information

Find the fraction of standard normal distribution observations that satisfy each of the following statements using Table A. Draw a standard normal curve in each scenario and shade the area under the curve that corresponds to the answer to the question.

Part (d) Step 2: Explanation

From the Standard Normal probabilities table, the area to the left of $z=-1.27$is $0.1020$and the area to the left of $z=-2.95$is $0.0016$. The area between $z=-2.95$and $z=-1.27$is the area to the left of $-1.27$minus the area to the left of $-2.95$.

Therefore, the area between $z=-2.95\&z=-1.27$is $0.1020-0.0016=0.1004$.