Question

Use Table A in the back of the book to find the proportion of observations from a standard Normal distribution that fall in each of the following regions. In each case, sketch a standard Normal curve and shade the area representing the region.

$\text{3.}-0.56<z<1.81$

Short answer

The standard Normal curve, with the region represented by the area, is as follows:

Step-by-step solution

Given Information   

Z-score :$-0.56<z<1.81$

Explanation   

From table A,

$$\begin{gathered} \mathrm{p}(-0.56<\mathrm{z}<1.81)=\mathrm{p}(\mathrm{z}<1.81)-\mathrm{p}(<-0.56) \\ =\mathrm{p}(\mathrm{z}<1.81)-[1-\mathrm{p}(\mathrm{z}<0.56\left)\right] \\ =0.9649-[1-0.7123] \\ =0.9648-0.2877 \\ =0.6771 \end{gathered}$$