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A beef rancher randomly sampled 42cattle from her large herd to obtain a 95%confidence interval to estimate the mean weight of the cows in the herd. The interval obtained was 1010,1321. If the rancher had used a 98%confidence interval instead, the interval would have been

(a) wider and would have less precision than the original estimate.

(b) wider and would have more precision than the original estimate.

(c) wider and would have the same precision as the original estimate.

(d) narrower and would have less precision than the original estimate.

(e) narrower and would have more precision than the original estimate.

Short Answer

Expert verified

Wider and would have been less precision than original.

Step by step solution

01

Given information

We have been given98%confidence interval instead of a 95%confidence interval.

02

Explanation

As the confidence level increases, we will be more sure about the true mean thus it needs to contain more possible values which implies that confidence level is much wider.

As the confidence interval is wider , our estimate is less accurate.

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Most popular questions from this chapter

A 96% confidence interval for the proportion of the labor force that is unemployed in a certain city is (0.07,0.10). Which of the following statements about this interval is true?

(a) The probability is 0.96that between 7%and 10%of the labor force is unemployed.

(b) About 96%of the intervals constructed by this method will contain the true proportion of unemployed in the city.

(c) The probability is 0.04that less than 7%or more than 10%of the labor force is unemployed.

(d) The true rate of unemployment lies within this interval 96%of the time.

(e) Between 7%and 10%of the labor force is unemployed96% of the time.

Refer to Exercise16.

(a) Carry out a significance test at the α=0.05level.

(b) Construct and interpret a 95%confidence interval for the difference between the population proportions. Explain how the confidence interval is consistent with the results of the test in part (a).

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